MeshPass: Determine the Largest Fish that can Pass through a Net

Description Usage Arguments Details Value References Examples

Description

Determine the largest height (or depth) of a fish that can pass through a single diamond-shaped mesh of a net.

Usage

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MeshPass(BarMesh, H2WRatio, L2HRatio = NA, Plot = TRUE)

Arguments

BarMesh

A numeric scalar, the length of one side of a square mesh (in inches).

H2WRatio

A numeric scalar, the ratio of the height (vertex to vertex) of a single square mesh (oriented as a diamond) to its width (vertex to vertex).

L2HRatio

A numeric scalar, > 1, the ratio of the length of a fish to its height (or depth). If set to NA, the default, no length calculations will be done.

Plot

A logical scalar, indicating if a diagram (drawn to scale) of the mesh and the largest fish should be shown, default TRUE.

Details

The cross sectional shape of the fish (looking it right in the nose) is assumed to be a geometric shape similar to an ellipse, two vertically-oriented tangential circles of equal size (like a figure 8).

Value

A named vector with 2 elements: fish height (in inches) and fish length (in mm).

References

This function is based on a modification of MATLAB [link] code provided by Kresimir Williams, NOAA-AFSC afsc.noaa.gov, at the Great Lakes Acoustic Users Group's Workshop on Trawl Performance, hosted by the Great Lakes Fishery Commission glfc.org, 22-24 April 2014, in Ann Arbor, Michigan, USA.

Examples

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MeshPass(BarMesh=2, H2WRatio=0.3)
MeshPass(BarMesh=2, H2WRatio=0.3, L2HRatio=4)
MeshPass(BarMesh=2, H2WRatio=1/0.3, L2HRatio=4)

JVAdams/artiFISHal documentation built on May 7, 2019, 10:14 a.m.