require(data.table) knitr::opts_chunk$set( comment = "#", error = FALSE, tidy = FALSE, cache = FALSE, collapse = TRUE )
In this vignette you will learn how to perform any join operation using resources available in the data.table
syntax.
It assumes familiarity with the data.table
syntax. If that is not the case, please read the following vignettes:
vignette("datatable-intro", package="data.table")
vignette("datatable-reference-semantics", package="data.table")
vignette("datatable-keys-fast-subset", package="data.table")
To illustrate how to use the method available with real life examples, let's simulate a normalized database from a little supermarket by performing the following steps:
data.table
where each product is represented by a row with some qualities, but leaving one product without id
to show how the framework deals with missing values.Products = data.table( id = c(1:4, NA_integer_), name = c("banana", "carrots", "popcorn", "soda", "toothpaste"), price = c(0.63, 0.89, 2.99, 1.49, 2.99), unit = c("unit", "lb", "unit", "ounce", "unit"), type = c(rep("natural", 2L), rep("processed", 3L)) ) Products
data.table
showing the proportion of taxes to be applied for processed products based on their units.NewTax = data.table( unit = c("unit","ounce"), type = "processed", tax_prop = c(0.65, 0.20) ) NewTax
data.table
simulating the products received every Monday with a product_id
that is not present in the Products
table.set.seed(2156) ProductReceived = data.table( id = 1:10, date = seq(from = as.IDate("2024-01-08"), length.out = 10L, by = "week"), product_id = sample(c(NA_integer_, 1:3, 6L), size = 10L, replace = TRUE), count = sample(c(50L, 100L, 150L), size = 10L, replace = TRUE) ) ProductReceived
data.table
to show some sales that can take place on weekdays with another product_id
that is not present in the Products
table.sample_date = function(from, to, size, ...){ all_days = seq(from = from, to = to, by = "day") weekdays = all_days[wday(all_days) %in% 2:6] days_sample = sample(weekdays, size, ...) days_sample_desc = sort(days_sample) days_sample_desc } set.seed(5415) ProductSales = data.table( id = 1:10, date = ProductReceived[, sample_date(min(date), max(date), 10L)], product_id = sample(c(1:3, 7L), size = 10L, replace = TRUE), count = sample(c(50L, 100L, 150L), size = 10L, replace = TRUE) ) ProductSales
data.table
joining syntaxBefore taking advantage of the data.table
syntax to perform join operations we need to know which arguments can help us to perform successful joins.
The next diagram shows a description for each basic argument. In the following sections we will show how to use each of them and add more complexity little by little.
x[i, on, nomatch] | | | | | | | \__ If NULL only returns rows linked in x and i tables | | \____ a character vector o list defining match logict | \_____ primary data.table, list or data.frame \____ secondary data.table
Please keep in mind that the standard argument order in data.table is
dt[i, j, by]
. For join operations, it is recommended to pass theon
andnomatch
arguments by name to avoid usingj
andby
when they are not needed.
This the most common and simple case as we can find common elements between tables to combine.
The relationship between tables can be:
In most of the following examples we will perform one to many matches, but we are also going to take the time to explain the resources available to perform many to many matches.
Use this method if you need to combine columns from 2 tables based on one or more references but keeping all rows present in the table located on the right (in the the square brackets).
In our supermarket context, we can perform a right join to see more details about the products received as this is relation one to many by passing a vector to the on
argument.
Products[ProductReceived, on = c(id = "product_id")]
As many things have changed, let's explain the new characteristics in the following groups:
x
table.i
table.If the join operation presents a present any name conflict (both table have same column name) the prefix i.
is added to column names from the right-hand table (table on i
position).
Row level
product_id
present on the ProductReceived
table in row 1 was successfully matched with missing id
of the Products
table, so NA
values are treated as any other value.i
table were kept including:product_id = 6
.product_id
several times.If you are following the vignette, you might have found out that we used a vector to define the relations between tables in the on
argument, that is really useful if you are creating your own functions, but another alternative is to use a list to define the columns to match.
To use this capacity, we have 2 equivalent alternatives:
list
function.Products[ProductReceived, on = list(id = product_id)]
list
alias .
.Products[ProductReceived, on = .(id = product_id)]
on
argumentIn all the prior example we have pass the column names we want to match to the on
argument but data.table
also have alternatives to that syntax.
Products
table from id
to product_id
and use the keyword .NATURAL
.ProductsChangedName = setnames(copy(Products), "id", "product_id") ProductsChangedName ProductsChangedName[ProductReceived, on = .NATURAL]
ProductsKeyed = setkey(copy(Products), id) key(ProductsKeyed) ProductReceivedKeyed = setkey(copy(ProductReceived), product_id) key(ProductReceivedKeyed) ProductsKeyed[ProductReceivedKeyed]
Most of the time after a join is complete we need to make some additional transformations. To make so we have the following alternatives:
[]
.j
argument.Our recommendation is to use the second alternative if possible, as it is faster and uses less memory than the first one.
The j
argument has great alternatives to manage joins with tables sharing the same names for several columns. By default all columns are taking their source from the the x
table, but we can also use the x.
prefix to make clear the source and use the prefix i.
to use any column form the table declared in the i
argument of the x
table.
Going back to the little supermarket, after updating the ProductReceived
table with the Products
table, it seems convenient apply the following changes:
id
to product_id
and from i.id
to received_id
.total_value
.Products[ ProductReceived, on = c("id" = "product_id"), j = .(product_id = x.id, name = x.name, price, received_id = i.id, date = i.date, count, total_value = price * count) ]
We can also use this alternative to return aggregated results based columns present in the x
table.
For example, we might interested in how much money we expend buying products each date regardless the products.
dt1 = ProductReceived[ Products, on = c("product_id" = "id"), by = .EACHI, j = .(total_value_received = sum(price * count)) ] dt2 = ProductReceived[ Products, on = c("product_id" = "id"), ][, .(total_value_received = sum(price * count)), by = "product_id" ] identical(dt1, dt2)
So far we have just joined data.table
base on 1 column, but it's important to know that the package can join tables matching several columns.
To illustrate this, let's assume that we want to add the tax_prop
from NewTax
to update the Products
table.
NewTax[Products, on = c("unit", "type")]
Use this method if you need to combine columns from 2 tables based on one or more references but keeping only rows matched in both tables.
To perform this operation we just need to add nomatch = NULL
or nomatch = 0
to any of the prior join operations to return the same results.
# First Table Products[ProductReceived, on = c("id" = "product_id"), nomatch = NULL] # Second Table ProductReceived[Products, on = .(product_id = id), nomatch = NULL]
Despite both tables have the same information, they present some relevant differences:
id
column of first table has the same information as the product_id
in the second table.i.id
column of first table has the same information as the id
in the second table.This method keeps only the rows that don't match with any row of a second table.
To apply this technique we just need to negate (!
) the table located on the i
argument.
Products[!ProductReceived, on = c("id" = "product_id")]
As you can see, the result only has 'banana', as it was the only product that is not present in the ProductReceived
table.
ProductReceived[!Products, on = c("product_id" = "id")]
In this case, the operation returns the row with product_id = 6,
as it is not present on the Products
table.
This method extract keeps only the rows that match with any row in a second table without combining the column of the tables.
It's very similar to subset as join, but as in this time we are passing a complete table to the i
we need to ensure that:
Any row in the x
table is duplicated due row duplication in the table passed to the i
argument.
All the renaming rows from x
should keep the original row order.
To make this, you can apply the following steps:
which = TRUE
to save the row numbers related to each matching row of the x
table.SubSetRows = Products[ ProductReceived, on = .(id = product_id), nomatch = NULL, which = TRUE ] SubSetRows
SubSetRowsSorted = sort(unique(SubSetRows)) SubSetRowsSorted
x
rows to keep.Products[SubSetRowsSorted]
Use this method if you need to combine columns from 2 tables based on one or more references but keeping all rows present in the table located on the left.
To perform this operation, we just need to exchange the order between both tables and the columns names in the on
argument.
ProductReceived[Products, on = list(product_id = id)]
Here some important considerations:
ProductReceived
table as it is the x
table.Products
table as it is the i
table.It didn't add the prefix i.
to any column.
Row level
i
table were kept as we never received any banana but row is still part of the results.product_id = 6
is no part of the results any more as it is not present in the Products
table.One of the key features of data.table
is that we can apply several operations before saving our final results by chaining brackets.
DT[ ... ][ ... ][ ... ]
So far, if after applying all that operations we want to join new columns without removing any row, we would need to stop the chaining process, save a temporary table and later apply the join operation.
To avoid that situation, we can use special symbols .SD
, to apply a right join based on the changed table.
NewTax[Products, on = c("unit", "type") ][, ProductReceived[.SD, on = list(product_id = id)], .SDcols = !c("unit", "type")]
Sometimes we want to join tables based on columns with duplicated id
values to later perform some transformations later.
To illustrate this situation let's take as an example the product_id == 1L
, which have 4 rows in our ProductReceived
table.
ProductReceived[product_id == 1L]
And 4 rows in our ProductSales
table.
ProductSales[product_id == 1L]
To perform this join we just need to filter product_id == 1L
in the i
table to limit the join just to that product and set the argument allow.cartesian = TRUE
to allow combining each row from one table with every row from the other table.
ProductReceived[ProductSales[list(1L), on = "product_id", nomatch = NULL], on = "product_id", allow.cartesian = TRUE]
Once we understand the result, we can apply the same process for all products.
ProductReceived[ProductSales, on = "product_id", allow.cartesian = TRUE]
allow.cartesian
is defaulted to FALSE as this is seldom what the user wants, and such a cross join can lead to a very large number of rows in the result. For example, if Table A has 100 rows and Table B has 50 rows, their Cartesian product would result in 5000 rows (100 * 50). This can quickly become memory-intensive for large datasets.
After joining the table we might find out that we just need to return a single join to extract the information we need. In this case we have 2 alternatives:
id = 2
.ProductReceived[ProductSales[product_id == 1L], on = .(product_id), allow.cartesian = TRUE, mult = "first"]
id = 9
.ProductReceived[ProductSales[product_id == 1L], on = .(product_id), allow.cartesian = TRUE, mult = "last"]
If you want to get all possible row combinations regardless of any particular id column we can follow the next process:
ProductsTempId = copy(Products)[, temp_id := 1L]
AllProductsMix = ProductsTempId[ProductsTempId, on = "temp_id", allow.cartesian = TRUE] AllProductsMix[, temp_id := NULL] # Removing type to make easier to see the result when printing the table AllProductsMix[, !c("type", "i.type")]
Use this method if you need to combine columns from 2 tables based on one or more references without removing any row.
As we saw in the previous section, any of the prior operations can keep the missing product_id = 6
and the soda (product_id = 4
) as part of the results.
To save this problem, we can use the merge
function even thought it is lower than using the native data.table
's joining syntax.
merge(x = Products, y = ProductReceived, by.x = "id", by.y = "product_id", all = TRUE, sort = FALSE)
A non-equi join is a type of join where the condition for matching rows is not based on equality, but on other comparison operators like <, >, <=, or >=. This allows for more flexible joining criteria. In data.table
, non-equi joins are particularly useful for operations like:
It's a great alternative if after applying a right of inner join:
x
(secondary data.table) in the final table.To illustrate how this work, let's center over attention on how are the sales and receives for product 2.
ProductSalesProd2 = ProductSales[product_id == 2L] ProductReceivedProd2 = ProductReceived[product_id == 2L]
If want to know, for example, if can find any receive that took place before a sales date, we can apply the next code.
ProductReceivedProd2[ProductSalesProd2, on = "product_id", allow.cartesian = TRUE ][date < i.date]
What does happen if we just apply the same logic on the list passed to on
?
As this opperation it's still a right join, it returns all rows from the i
table, but only shows the values for id
and count
when the rules are met.
The date related ProductReceivedProd2
was omited from this new table.
ProductReceivedProd2[ProductSalesProd2, on = list(product_id, date < date)]
Now, after applying the join, we can limit the results only show the cases that meet all joining criteria.
ProductReceivedProd2[ProductSalesProd2, on = list(product_id, date < date), nomatch = NULL]
Rolling joins are particularly useful in time-series data analysis. They allow you to match rows based on the nearest value in a sorted column, typically a date or time column.
This is valuable when you need to align data from different sources that may not have exactly matching timestamps, or when you want to carry forward the most recent value.
For example, in financial data, you might use a rolling join to assign the most recent stock price to each transaction, even if the price updates and transactions don't occur at the exact same times.
In our supermarket example, we can use a rolling join to match sales with the most recent product information.
Let's assume that the price for Bananas and Carrots changes at the first date of each month.
ProductPriceHistory = data.table( product_id = rep(1:2, each = 3), date = rep(as.IDate(c("2024-01-01", "2024-02-01", "2024-03-01")), 2), price = c(0.59, 0.63, 0.65, # Banana prices 0.79, 0.89, 0.99) # Carrot prices ) ProductPriceHistory
Now, we can perform a right join giving a different prices for each product based on the sale date.
ProductPriceHistory[ProductSales, on = .(product_id, date), roll = TRUE, j = .(product_id, date, count, price)]
If we just want to see the matching cases we just need to add the argument nomatch = NULL
to perform an inner rolling join.
ProductPriceHistory[ProductSales, on = .(product_id, date), roll = TRUE, nomatch = NULL, j = .(product_id, date, count, price)]
As we just saw in the prior section the x
table gets filtered by the values available in the i
table. Actually, that process is faster than passing a Boolean expression to the i
argument.
To filter the x
table at speed we don't to pass a complete data.table
, we can pass a list()
of vectors with the values that we want to keep or omit from the original table.
For example, to filter dates where the market received 100 units of bananas (product_id = 1
) or popcorn (product_id = 3
) we can use the following:
ProductReceived[list(c(1L, 3L), 100L), on = c("product_id", "count")]
As at the end, we are filtering based on a join operation the code returned a row that was not present in original table. To avoid that behavior, it is recommended to always to add the argument nomatch = NULL
.
ProductReceived[list(c(1L, 3L), 100L), on = c("product_id", "count"), nomatch = NULL]
We can also use this technique to filter out any combination of values by prefixing them with !
to negate the expression in the i
argument and keeping the nomatch
with its default value. For example, we can filter out the 2 rows we filtered before.
ProductReceived[!list(c(1L, 3L), 100L), on = c("product_id", "count")]
If you just want to filter a value for a single character column, you can omit calling the list()
function pass the value to been filtered in the i
argument.
Products[c("banana","popcorn"), on = "name", nomatch = NULL] Products[!"popcorn", on = "name"]
The :=
operator in data.table is used for updating or adding columns by reference. This means it modifies the original data.table without creating a copy, which is very memory-efficient, especially for large datasets. When used inside a data.table, :=
allows you to add new columns or modify existing ones as part of your query.
Let's update our Products
table with the latest price from ProductPriceHistory
:
copy(Products)[ProductPriceHistory, on = .(id = product_id), j = `:=`(price = tail(i.price, 1), last_updated = tail(i.date, 1)), by = .EACHI][]
In this operation:
copy
prevent that :=
changes by reference the Products
table.sProducts
with ProductPriceHistory
based on id
and product_id
.price
column with the latest price from ProductPriceHistory
.last_updated
column to track when the price was last changed.by = .EACHI
ensures that the tail
function is applied for each product in ProductPriceHistory
.Understanding data.table Rolling Joins: https://www.r-bloggers.com/2016/06/understanding-data-table-rolling-joins/
Semi-join with data.table: https://stackoverflow.com/questions/18969420/perform-a-semi-join-with-data-table
Cross join with data.table: https://stackoverflow.com/questions/10600060/how-to-do-cross-join-in-r
How does one do a full join using data.table?: https://stackoverflow.com/questions/15170741/how-does-one-do-a-full-join-using-data-table
Enhanced data.frame: https://rdatatable.gitlab.io/data.table/reference/data.table.html
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