ion_balance | R Documentation |
anion sum = Sulphate\*0.0208 + Chloride\*0.0282 + Bicarbonate\*0.0164 + Carbonate\*0.0333
cation sum = Calcium\*0.0499 + Magnesium\*0.0822 + Sodium\*0.0435 + Potassium\*0.0256 + Silica\*0.02629
ion percent difference = (cation sum - anion sum)/(cation sum + anion sum)\*100
Calculate the ion balance Calculate the ion balance, equal to:
anion sum = Sulphate\*0.0208 + Chloride\*0.0282 + Bicarbonate\*0.0164 + Carbonate\*0.0333
cation sum = Calcium\*0.0499 + Magnesium\*0.0822 + Sodium\*0.0435 + Potassium\*0.0256 + Silica\*0.02629
ion percent difference = (cation sum - anion sum)/(cation sum + anion sum)\*100
ion_balance(column_names, labdat)
column_names |
string vector defined in apply_calculations. The desired final columns for each calculated dataframe |
labdat |
dataframe containing the parsed lab data |
dataframe containing all required columns, including the calculated
result. Note that the results of determine_NA_NC()
are employed, and that
parameters for which a value cannot be calculated are assigned NA or NaN, as
defined in the function description
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