View source: R/ch.getProbMax.r
ch.getProbMax | R Documentation |
This function calculates probMax for chMaxAveComb based on the percent influence of the maximum valued item
ch.getProbMax(
list.data,
percentMaxInfluenceOverall = 0.6,
percentMaxInfluenceOnAve = NULL
)
list.data |
A list with each element filled with numbers. Each vactor in the list is a set of values for an item |
percentMaxInfluenceOverall |
A probability that specifies the percent of influence that the column with the max(median()) has on the output vector over and above the average. When percentMaxInfluenceOverall = 0, then the max(median()) has no influence over and above the average. It's only influence is that it is part of the average. When percentMaxInfluenceOverall > 0, then max(median()) has some influence on the average, but also some more influence over and above the average. When percentMaxInfluenceOverall = 1, then max(median()) has all the influence. pDEFAULT = 0.6 (this is the percent found with the biased average grouping model; |
percentMaxInfluenceOnAve |
A probability that specifies the percent of influence that the column with the max(median()) has on the the average. When percentMaxInfluenceOnAve = 0, then the max(median()) has no influence the average. When percentMaxInfluence > 0, then max(median()) has some influence on the average. When percentMaxInfluence = 1, then max(median()) has all the influence. pDEFAULT = NULL (this will force the column with the max(median()) to have an equal influence on the ave as all other columns); |
a probability to be input into ch.maxAveComb for the probMax option
ch.maxAveComb (list.data, percentMaxInfluence = .6)
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