Description Usage Arguments Details Value Author(s) Examples
Brass' relational model of mortility makes use of a standard model mortility schedule, based on $L_x^s$ that is linearised using
Y_s(x) = \frac{1}{2} \ln ≤ft( \frac{a l_0 - L_x^s}{L_x^s} \right)
where l_0 is the population of the cohort at age zero.
1 2 | brass_mort(model = NULL, x = seq(from = 0, to = 100, by = 1), alpha = 0,
beta = 1, l0 = 1e+05)
|
model |
Vector of a 'model' age specific person years lived schedule $L_x$. Will be used to derive the standardised transformed age schedule, \Y_s(x) above. |
x |
Vector for the sequence of ages. |
alpha |
Numeric value for intercept adjustment to the standardised transformed age schedule |
beta |
Numeric value for slope adjustment to the standardised transformed age schedule |
The modified transformed schedule is formed by adjusting the demographer's logit above using
Y(x) = α + β Y_s(x)
where β changes the slope and α the intercept of the linearised $L_x$
The modified transformed schedule is converted back into $L_x$ by applying the anti-function used to linearise the standard schedule.
Returns vector of $L_x$ from the relational model schedule. The function is primarily intended for creating synthetic survivorships for projection models.
The alpha
and beta
parameters relate a modified schedule to the schedule provided by the model
argument.
Guy J. Abel
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