YearsMonthsDays: Convert fractional years into a lubridate period object
In grfiv/ustreasuries: Treasury Data Download, Fixed-Income Models and Derivative Analyses
Description
Usage
Arguments
Value
Author(s)
Examples
Description
Given a fractional number of years you need to convert into years, months and
days to do date math
See the example for the conversion
Usage
1
YearsMonthsDays(years)
Arguments
years
Fractional years: 2 years, 3 months, 10 days = 2 + 3/12 + 10/365 = 2.277397
Value
a lubridate period object
Author(s)
George Fisher
Examples
1
2
3
4
5
library(ustreasuries)
(diff_tm <- YearsMonthsDays(2 + 3/12 + 10/365))
# July 1, 2000 plus 2 years (2002), 3 months (10), 10 days (11)
as.Date(lubridate::ymd("2000/07/01") + diff_tm)
grfiv/ustreasuries documentation built on May 17, 2019, 8:36 a.m.
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Description Usage Arguments Value Author(s) Examples
Description
Given a fractional number of years you need to convert into years, months and days to do date math
See the example for the conversion
Usage
1 | YearsMonthsDays(years)
|
Arguments
years |
Fractional years: 2 years, 3 months, 10 days = 2 + 3/12 + 10/365 = 2.277397 |
Value
a lubridate period object
Author(s)
George Fisher
Examples
1 2 3 4 5 | library(ustreasuries)
(diff_tm <- YearsMonthsDays(2 + 3/12 + 10/365))
# July 1, 2000 plus 2 years (2002), 3 months (10), 10 days (11)
as.Date(lubridate::ymd("2000/07/01") + diff_tm)
|
R Package Documentation
Browse R Packages
We want your feedback!
Note that we can't provide technical support on individual packages. You should contact the package authors for that.
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