find_word: Find words that fit the chosen parameters.

In idmn/wfindr: Crossword, Scrabble and Anagram Solver

Description

Uses regex constructed by model_to_regex to search words. By default the search is done among words.eng.
find_word returns a vector of found words, find_word_l returns a logical vector that can be used for subsetting.

Usage

find_word(model = "*", allow = letters, ban = character(0),
  type = "usual", words = wfindr::words.eng)

find_word_l(model = "*", allow = letters, ban = character(0),
  type = "usual", words = wfindr::words.eng)

Arguments

model	pattern that a word should match. Consists of letters and unknown characters specifications. Dot . stands for unknown character. It may be followed by {...} repetition quantifier (i.e. .{n}, .{n,}, .{n,m}). Asterisk * stands for unknown number of unknown characters. See examples. By default model is set to "*".
allow	characters allowed to fill gaps in a word. Can be listed in a single string or in a vector. By default is set to letters.
ban	characters not allowed to fill gaps in a word.
type	can be "usual", "scrabble", or "anagram". Abbreviated input is allowed: e.g. "u", "s", or "a". type defines how often allowed characters can be used to fill the gaps. Say, character appears n times in allow and m times in ban. If d = n - m is less or equal to zero, whatever the type is, this character won't be used to fill the gaps. For the case when d > 0: If type is "usual" then the character is allowed to fill the gaps unlimited number of times. If type is "scrabble" then the character is allowed to fill the gaps no more than d times. If type is "anagram" then the character should be used exactly d times.
words	vector of words to search within. By default is set to words.eng.

See Also

scrabble, anagram

Examples

## Search 4-letter words starting with "c".
find_word("c.{3}")
## Disallow "a" and "b".
find_word("c.{3}", ban = "ab")
## Allow only "a" and "b" to fill the gap.
find_word("c.{3}", allow = "ab")
## Allow "a", "b", and "c", but then ban "c"
## result is the same as in the previous example
find_word("c.{3}", allow = "abc", ban = "c")

## Find no more than 4-letter words that have "th" bigram
library(magrittr)
find_word(".{0,4}") %>% find_word("*th*", words = .)
## count words that start with "th"
sum(find_word_l("th*"))
length(find_word("th*"))

## Find words that can be constructed of the "thing" word's letters.
find_word(allow = "thing", type = "scrabble")
## Get at lest 4-letter words.
find_word(".{4,}", allow = "thing", type = "scrabble")

## Find anagrams of the word "thing"
find_word(allow = "thing", type = "anagram")

idmn/wfindr documentation built on May 18, 2019, 2:33 a.m.