nroot: Compute bth root of a This is a so-called Vectorized...
In ifrit98/museR:
Description
This does *not* handle the case where b is the inverse of an integer
(e.g. nthroot(-1,1/3) ==? (-1)^3), since in general you cannot count
on 1/(1/int) being an integer.
If on the other hand you want the complex principal value of the nth
root, you can use (a+0i)^(1/b).
Usage
1
nroot(a, b)
ifrit98/museR documentation built on May 25, 2020, 6:12 a.m.
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Description
This does *not* handle the case where b is the inverse of an integer (e.g. nthroot(-1,1/3) ==? (-1)^3), since in general you cannot count on 1/(1/int) being an integer. If on the other hand you want the complex principal value of the nth root, you can use (a+0i)^(1/b).
Usage
1 | nroot(a, b)
|
R Package Documentation
Browse R Packages
We want your feedback!
Note that we can't provide technical support on individual packages. You should contact the package authors for that.
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