make_stationary_fert_rates: Calculate the fertility rates that would produce a stationary...
In johnrbryant/agesim: Simulate Age Structures in Small Populations

Description Usage Arguments Details Value See Also Examples

View source: R/make_stationary_fert_rates.R

Given a set of Lx, and an age pattern for fertility, calculate the age-sex-specific fertility rates that would produce a stationary (ie zero growth rate) population.

1	make_stationary_fert_rates(Lx, propn_age_fert, sex_ratio)

`Lx`	A `Counts` array with the life table Lx values.
`propn_age_fert`	A `Values` with the age-distribution of fertility rates.
`sex_ratio`	The number of male births per 100 female births.

Lx must be a Counts array with two dimensions. The dimensions of Lx must have dimtype "age" and "sex". The "age" dimension must have dimscale "Intervals".

propn_age_fert must be a Counts array, with a single dimension. The dimension must have dimtype "age", and dimscale "Intervals".

A Values object with "age" and "sex" dimensions.

Lx_west, propn_age_fert_booth, make_stationary_fert_rates

Lx <- dembase::Counts(Lx_west[ , , "10"])
propn_age_fert <- dembase::Values(propn_age_fert_booth)
make_stationary_fert_rates(Lx = Lx,
                           propn_age_fert = propn_age_fert,
                           sex_ratio = 105)