construct_filter: Construct SPARQL filter

In konradedgar/SmarterScotland: Source Public Data from statistics.gov.scot

Description

This query derives SPARQL filter statement using the IN syntax.

Usage

construct_filter(sparql_variable, filter_values, use_str = FALSE)

Arguments

sparql_variable	A character scalar to be used in IN clause, without ?.
filter_values	A vector of filter values to be verified against in the filter statement.
use_str	A logical, defaults to FALSE, if TRUE it produces str(?variable) instead of ?variable.

Details

For instance, arguments sparql_variable = "time" and filter_values = c(2011, 2012) will result in a expression FILTER (?time IN ( "2011, 2012" )).

Value

A character scalar corresponding to SPARQL filter expression.

Examples

# This function is not exported from the package as it's mostly used
# internally.
SmarterScotland:::construct_filter(sparql_variable = "time",
                                   filter_values = c(2011, 2012))
SmarterScotland:::construct_filter(sparql_variable = "time", use_str = TRUE,
                                   filter_values = c(2011, 2012))

konradedgar/SmarterScotland documentation built on Oct. 3, 2019, 11:46 a.m.