Description Usage Arguments Value Life cycle Examples
questioning
lst()
constructs a list, similar to base::list()
, but with some of the
same features as tibble()
. lst()
builds components sequentially. When
defining a component, you can refer to components created earlier in the
call. lst()
also generates missing names automatically.
1 |
... |
A set of name-value pairs. Arguments are evaluated sequentially,
so you can refer to previously created elements. These arguments are
processed with |
A named list.
The lst()
function is in the questioning stage. It is essentially
rlang::list2()
, but with a couple features copied from tibble()
. It's not
clear that a function for creating lists belongs in the tibble package.
Consider using rlang::list2()
instead.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 | # the value of n can be used immediately in the definition of x
lst(n = 5, x = runif(n))
# missing names are constructed from user's input
lst(1:3, z = letters[4:6], runif(3))
a <- 1:3
b <- letters[4:6]
lst(a, b)
# pre-formed quoted expressions can be used with lst() and then
# unquoted (with !!) or unquoted and spliced (with !!!)
n1 <- 2
n2 <- 3
n_stuff <- quote(n1 + n2)
x_stuff <- quote(seq_len(n))
lst(!!!list(n = n_stuff, x = x_stuff))
lst(n = !!n_stuff, x = !!x_stuff)
lst(n = 4, x = !!x_stuff)
lst(!!!list(n = 2, x = x_stuff))
|
Add the following code to your website.
For more information on customizing the embed code, read Embedding Snippets.