rayleigh: Estimates reyleigh number, given a period

In mcrucifix/iceages: Ice age models and analysis

Estimates reyleigh number, given a period

Usage

rayleigh(model, par, init, t_0, t_1, DT, n = as.integer(250), ncores = 1, ...)

Arguments

model
par
init
t_0
t_1
DT
n
ncores
...

Examples

##---- Should be DIRECTLY executable !! ----
##-- ==>  Define data, use random,
##--	or do  help(data=index)  for the standard data sets.

## The function is currently defined as
function (model, par, init, t_0, t_1, DT, n = as.integer(250), 
    ncores = 1, ...) 
{
    N <- nrow(par)
    state <- matrix(init, N, length(init), byrow = TRUE)
    state <- propagate_1step_D_multicore(model, NULL, state, 
        par, t_0, t_1, ncores = ncores, ...)$state
    if (t_1 <= t_0) 
        stop("t_1 must be greater than t_0")
    if (DT <= 0) 
        stop("DT must be strictly positive")
    if (as.integer(n) <= 0) 
        stop("as.integer(n) must be at least 1")
    norm <- function(state) sqrt(apply(state * state, 1, sum))
    sum_states = state * 0
    sum_norm = rep(0, N)
    for (i in seq(0, n)) {
        t <- t_1 + i * DT
        t_2 <- t + DT
        state <- propagate_1step_D_multicore(model, NULL, state, 
            par, t, t_2, ncores = ncores, ...)$state
        sum_states <- sum_states + state
        sum_norm <- sum_norm + norm(state)
    }
    return(norm(sum_states)/sum_norm)
  }

mcrucifix/iceages documentation built on June 9, 2024, 9:37 a.m.