| sqrt_x | R Documentation | 
Perform a sqrt (x+a) normalization transformation
sqrt_x(x, a = NULL, standardize = TRUE, ...)
## S3 method for class 'sqrt_x'
predict(object, newdata = NULL, inverse = FALSE, ...)
## S3 method for class 'sqrt_x'
print(x, ...)
| x | A vector to normalize with with x | 
| a | The constant to add to x (defaults to max(0, -min(x))) | 
| standardize | If TRUE, the transformed values are also centered and scaled, such that the transformation attempts a standard normal | 
| ... | additional arguments | 
| object | an object of class 'sqrt_x' | 
| newdata | a vector of data to be (potentially reverse) transformed | 
| inverse | if TRUE, performs reverse transformation | 
sqrt_x performs a simple square-root transformation in the
context of bestNormalize, such that it creates a transformation that can be
estimated and applied to new data via the predict function. The
parameter a is essentially estimated by the training set by default
(estimated as the minimum possible), while the base
must be specified beforehand.
A list of class sqrt_x with elements 
| x.t | transformed original data | 
| x | original data | 
| mean | mean after transformation but prior to standardization | 
| sd | sd after transformation but prior to standardization | 
| n | number of nonmissing observations | 
| norm_stat | Pearson's P / degrees of freedom | 
| standardize | was the transformation standardized | 
The predict function returns the numeric value of the transformation
performed on new data, and allows for the inverse transformation as well.
x <- rgamma(100, 1, 1)
sqrt_x_obj <- sqrt_x(x)
sqrt_x_obj
p <- predict(sqrt_x_obj)
x2 <- predict(sqrt_x_obj, newdata = p, inverse = TRUE)
all.equal(x2, x)
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