| str.left.of | R Documentation |
Returns the substring left to the first occurence of pattern
## S3 method for class 'left.of' str(str, pattern, ..., not.found = str)
## Not run:
str = c("a = 5","b+3","a+3 = 4 = 3", "=")
str.left.of(str,"=")
str.left.of(str,"=", not.found=NA)
str.right.of(str,"=")
str.right.of(str,"=", not.found=NA)
## End(Not run)
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