#' Find maximum profit for Pure Bundling strategy
#'
#' @param r1.r2 NX2 reservation prices of two goods []
#' @param pb.min.max Vector
#' @param c.1 good 1 parameter of production cost
#' @param c.2 good 1 parameter of production cost
#' @param alfa parameter of scale economics alfa = 0 --> CRS, alfa < 0 --> IRS, alfa < 0 --> DRS
#' @param beta parameter of sope economics beta = 0 --> neutral, beta > 0 complementary, beta < 0 substitution
#' @param teta parameter of complementary and substitution of goods beta = 0 --> neutral, beta > 0 complementary, beta < 0 substitution
#' @param FC fixed Cost of production
#'
#' @return max.profit
#'
#' @export
Zero.Profit.PB <- function(r1.r2, pb.min.max, c.1, c.2, alfa, beta,teta, FC) {
numerate <- max(pb.min.max)
FC <- FC/numerate
c.1 <- c.1/numerate
c.2 <- c.2/numerate
r1.r2 <- data.frame(r1.r2)/numerate
pb.min.max <- pb.min.max/numerate
step <- 0.001
prices.pb <- Prices.PB(pb.min.max, step)
output.i <-foreach(i = prices.pb, .combine="rbind",.packages = "bundling", .multicombine=TRUE) %dopar% {
p.b <- i # price Pure Bundling
output <- Profit.PB(r1.r2, p.b, c.1, c.2, alfa, beta, teta, FC)
list(output$profit,output$c.s,output$t.c,output$p.b )
}
output <- matrix(unlist(output.i), ncol = 4, byrow = FALSE)
ndx <- order(abs( 0 - output[,1]))[1:(round(nrow(output)/10, digits = 0))]
zero.profit <- output[ndx,]
ind.max.c.s <- apply(zero.profit, 2, max)[2]
zero.profit <- matrix((zero.profit[zero.profit[,2] == ind.max.c.s]),ncol = 4, byrow = FALSE)
remove("output")
output.zero.profit.PB <-
list(
zero.profit.aprox = zero.profit[1,1]*numerate,
zero.profit.c.s = zero.profit[1,2]*numerate,
zero.profit.t.c = zero.profit[1,3]*numerate,
zero.profit.p.b = zero.profit[1,4]*numerate)
return(output.zero.profit.PB)
}
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