date.mmddyy: Format a Julian date

In date: Functions for handling dates

Description

Given a vector of Julian dates, this returns them in the form “10/11/89”, “28/7/54”, etc.

Usage

date.mmddyy(sdate, sep = "/")

Arguments

sdate	A vector of Julian dates, e.g., as returned by mdy.date().
sep	Character string used to separate the month, day, and year portions of the returned string.

Value

A vector of character strings containing the formatted dates.

See Also

date.mdy, mdy.date, date.ddmmmyy

Examples

date.mmddyy(as.date(10))

Example output

[1] "1/11/60"

date documentation built on May 2, 2019, 5:22 p.m.