date.mmddyyyy: Format a Julian date

In date: Functions for handling dates

Description

Given a vector of Julian dates, this returns them in the form “10/11/1989”, “28/7/1854”, etc.

Usage

date.mmddyyyy(sdate, sep = "/")

Arguments

sdate	A vector of Julian dates, e.g., as returned by mdy.date().
sep	Character string used to separate the month, day, and year portions of the returned string.

Value

A vector of character strings containing the formatted dates.

See Also

date.mdy, mdy.date, date.ddmmmyy

Examples

date.mmddyyyy(as.date(1:10))

Example output

 [1] "1/2/1960"  "1/3/1960"  "1/4/1960"  "1/5/1960"  "1/6/1960"  "1/7/1960" 
 [7] "1/8/1960"  "1/9/1960"  "1/10/1960" "1/11/1960"

date documentation built on May 2, 2019, 5:22 p.m.