Survspline: Royston/Parmar spline survival distribution

In flexsurv: Flexible parametric survival models

Description

Probability density and distribution function for the Royston/Parmar spline model.

Usage

dsurvspline(x, gamma, beta=0, X=0, knots=c(-10,10), scale="hazard", offset=0)
psurvspline(q, gamma, beta=0, X=0, knots=c(-10,10), scale="hazard", offset=0)
hsurvspline(x, gamma, beta=0, X=0, knots=c(-10,10), scale="hazard", offset=0)
Hsurvspline(x, gamma, beta=0, X=0, knots=c(-10,10), scale="hazard", offset=0)

Arguments

x,q	Vector of times.
gamma	Vector of parameters describing the baseline spline function, as described in flexsurvspline.
beta	Vector of covariate effects.
X	Matrix of covariate values.
knots	Locations of knots on the axis of log time, supplied in increasing order. Unlike in flexsurvspline, these include the two boundary knots. If there are no additional knots, the boundary locations are not used. If there are one or more additional knots, the boundary knots should be at or beyond the minimum and maximum values of the log times. In flexsurvspline these are exactly at the minimum and maximum values.
scale	"hazard", "odds", or "normal", as described in flexsurvspline. With the default of no knots in addition to the boundaries, this model reduces to the Weibull, log-logistic and log-normal respectively.
offset	An extra constant to add to the linear predictor eta.

Value

dsurvspline gives the density, psurvspline gives the distribution function, hsurvspline gives the hazard and Hsurvspline gives the cumulative hazard, as described in flexsurvspline.

Author(s)

Christopher Jackson <[e-mail]>

References

Royston, P. and Parmar, M. (2002). Flexible parametric proportional-hazards and proportional-odds models for censored survival data, with application to prognostic modelling and estimation of treatment effects. Statistics in Medicine 21(1):2175-2197.

See Also

flexsurvspline.

Examples

## reduces to the weibull
regscale <- 0.786; cf <- 1.82
a <- 1/regscale; b <- exp(cf)
dweibull(1, shape=a, scale=b)
dsurvspline(1, gamma=c(log(1 / b^a), a)) # should be the same

## reduces to the log-normal
meanlog <- 1.52; sdlog <- 1.11
dlnorm(1, meanlog, sdlog) 
dsurvspline(1, gamma = c(-meanlog/sdlog, 1/sdlog), scale="normal")
# should be the same

Example output

Loading required package: survival
[1] 0.1137858
[1] 0.1137858
[1] 0.1407338
[1] 0.1407338

flexsurv documentation built on May 2, 2019, 6:23 p.m.