Nothing
Ispline <-
function(x,order,knots){
# I spline with degree=order, 1 for linear, 2 for quadratic, 3 for cubic, etc.
# x is a row vector
# knots are a sequence of increasing points containing the two end points of the interval (a, b), where the curve is to be estimated.
# The output is a matrix with dimension (length(knots)+order-2) by length(x).
k=order+1
m=length(knots)
n=m-2+k # number of parameters
t=c(rep(1,k)*knots[1], knots[2:(m-1)], rep(1,k)*knots[m]) # newknots
yy1=array(rep(0,(n+k-1)*length(x)),dim=c(n+k-1, length(x)))
for (l in k:n){
yy1[l,]=(x>=t[l] & x<t[l+1])/(t[l+1]-t[l])
}
yytem1=yy1
for (ii in 1:order){
yytem2=array(rep(0,(n+k-1-ii)*length(x)),dim=c(n+k-1-ii, length(x)))
for (i in (k-ii):n){
yytem2[i,]=(ii+1)*((x-t[i])*yytem1[i,]+(t[i+ii+1]-x)*yytem1[i+1,])/(t[i+ii+1]-t[i])/ii
}
yytem1=yytem2
}
index=rep(0,length(x))
for (i in 1:length(x)){
index[i]=sum(t<=x[i])
}
yy=array(rep(0,(n-1)*length(x)),dim=c(n-1,length(x)))
if (order==1){
for (i in 2:n){
yy[i-1,]=(i<index-order+1)+(i==index)*(t[i+order+1]-t[i])*yytem2[i,]/(order+1)
}
}else{
for (j in 1:length(x)){
for (i in 2:n){
if (i<(index[j]-order+1)){
yy[i-1,j]=1
}else if ((i<=index[j]) && (i>=(index[j]-order+1))){
yy[i-1,j]=(t[(i+order+1):(index[j]+order+1)]-t[i:index[j]])%*%yytem2[i:index[j],j]/(order+1)
}else{
yy[i-1,j]=0
}
}
}
}
return(yy)
}
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