View source: R/group.rankings.R
group | R Documentation |
Create an object of class "grouped_rankings"
which associates a
group index with an object of class "rankings"
. This allows the
rankings to be linked to covariates with group-specific values as the basis
for model-based recursive partitioning, see pltree
.
group(x, index, ...)
as.grouped_rankings(x, ...)
## S3 method for class 'paircomp'
as.grouped_rankings(x, ...)
## S3 method for class 'grouped_rankings'
x[i, j, ..., drop = TRUE, as.grouped_rankings = TRUE]
## S3 method for class 'grouped_rankings'
format(x, max = 2L, width = 20L, ...)
x |
a |
index |
a numeric vector of length equal to the number of rankings specifying the subject for each ranking. |
... |
additional arguments passed on to |
i |
indices specifying groups to extract, may be any data type accepted
by |
j |
indices specifying items to extract, as for |
drop |
if |
as.grouped_rankings |
if |
max |
the maximum number of rankings to format per subject. |
width |
the maximum width in number of characters to format each ranking. |
An object of class "grouped_rankings"
, which is a vector of
of group IDs with the following attributes:
rankings |
The |
index |
An index match each ranking to each group ID. |
R |
A matrix with items ordered from last to first place, for each ranking. |
S |
The rankings matrix with the ranks replaced by the size of the chosen set for free choices and zero for forced choices. |
id |
A list with elements of the adjacency matrix that are incremented by each ranking. |
pltree
# ungrouped rankings (5 rankings, 4 items)
R <- as.rankings(matrix(c(1, 2, 0, 0,
0, 2, 1, 0,
0, 0, 1, 2,
2, 1, 0, 0,
0, 1, 2, 3), ncol = 4, byrow = TRUE))
length(R)
R
# group rankings (first three in group 1, next two in group 2)
G <- group(R, c(1, 1, 1, 2, 2))
length(G)
## by default up to 2 rankings are shown per group, "..." indicates if
## there are further rankings
G
print(G, max = 1)
## select rankings from group 1
G[1,]
## exclude item 3 from ranking
G[, -3]
## rankings from group 2, excluding item 3
## - note group 2 becomes the first group
G[2, -3]
## index underlying rankings without creating new grouped_rankings object
G[2, -3, as.grouped_rankings = FALSE]
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