Rectify Date

Description

Rectify a date that may be out of wack.

Usage

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recdate(jd=0, hr=0, mi=0, sec=0, yr=0)
recdatel(X)

Arguments

jd

Julian Day

hr

hours

mi

minutes

sec

seconds

yr

year

or

X

list of date

Details

Returns date with correct numbers. So if number of seconds is greater than 60, will add to minutes...

Value

jd

Julian Day

hr

hours

mi

minutes

sec

seconds

yr

year

Note

Default value for jd is 1, the rest are 0. This function now should successfully span year breaks. Leap years are correctly accounted for too.

Author(s)

Jonathan M. Lees<jonathan.lees.edu>

See Also

showdatetime, DAYSperYEAR, fromjul,getjul, tojul, getmoday

Examples

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recdate(76, 23, 22, yr=2000)

###########  example spanning leap year
##  start on Day 1, but subtract 36 hours and proceed to plus 36 hours
hrs <- seq(from=-36, to=36, by=2)
rd <- recdate(jd=1, hr=hrs, mi=34,
       sec=23+runif(n=length(hrs), 0, 59) , yr=2009)
write.table(data.frame(rd))

###########  example spanning non-leap year
rd2 <- recdate(jd=1, hr=hrs, mi=34,
     sec=23+runif(n=length(hrs), 0, 59) , yr=2008)
write.table(data.frame(rd2))

Questions? Problems? Suggestions? or email at ian@mutexlabs.com.

Please suggest features or report bugs with the GitHub issue tracker.

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