okPython: Check for a Valid Python for Interface

Description Usage Arguments

View source: R/pythonInterface.R

Description

The function returns true or false according to whether a Python interface can be established. This will fail if no Python exists, if it is incompatible with this version of XRPython (e.g., 32 vs 64 bits in Windows), or if for some reason it can't evaluate a trivial expression correctly. Warnings are printed but ignored.

Usage

1
okPython(verbose = FALSE)

Arguments

verbose

Should a message with the cause of a failure be reported? Default FALSE.


XRPython documentation built on May 2, 2019, 9:33 a.m.