Description Usage Arguments Details Value Note Author(s) References See Also Examples
This function computes the test and key test quantities for the two one-sided test for equivalence, as documented in Schuirmann (1981) and Westlake (1981). This function computes the test from the statistics of a sample of paired differences of a normally-distributed population.
1 |
mean |
sample mean |
std |
sample standard deviation |
n |
sample size |
null |
the value of the parameter in the null hypothesis |
alpha |
test size |
Epsilon |
magnitude of region of similarity |
This test requires the assumption of normality of the population.
A list with the following components
Dissimilarity |
the outcome of the test of the null hypothesis of dissimilarity |
Mean |
the mean of the sample |
StdDev |
the standard deviation of the sample |
n |
the non-missing sample size |
alpha |
the size of the test |
Epsilon |
the magnitude of the region of similarity |
Interval |
the half-length of the two one-sided interval |
This test requires the assumption of normality of the population. The components of the test are t-based confidence intervals, so the Central Limit Theorem and Slutsky's Theorem may be relevant to its application in large samples.
Andrew Robinson A.Robinson@ms.unimelb.edu.au
Schuirmann, D.L. 1981. On hypothesis testing to determine if the mean of a normal distribution is contained in a known interval. Biometrics 37 617.
Wellek, S. 2003. Testing statistical hypotheses of equivalence. Chapman and Hall/CRC. 284 pp.
Westlake, W.J. 1981. Response to T.B.L. Kirkwood: bioequivalence testing - a need to rethink. Biometrics 37, 589-594.
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