Nothing
# QUANTITATIVE TEST ############################################################
testthat::test_that("linear rescaling correct", {
## exp = 10, cutoff = 5
testthat::expect_equal(
object = healthiar::get_risk(
exp = 10,
cutoff = 5,
rr = 1.1,
rr_increment = 10,
erf_shape = "linear"
),
expected = 1.05
)
## exp = 15, cutoff = 5
testthat::expect_equal(
object = healthiar::get_risk(
exp = 15,
cutoff = 5,
rr = 1.1,
rr_increment = 10,
erf_shape = "linear"
),
expected = 1.1
)
## exp = 0, cutoff = 0
testthat::expect_equal(
object = healthiar::get_risk(
exp = 0,
cutoff = 0,
rr = 1.1,
rr_increment = 10,
erf_shape = "linear"
),
expected = 1
)
## exp = 0, cutoff = 5
testthat::expect_equal(
object = healthiar::get_risk(
exp = 0,
cutoff = 5,
rr = 1.1,
rr_increment = 10,
erf_shape = "linear"
),
expected = 1
)
}
)
testthat::test_that("log-linear rescaling the same", {
## exp = 20, cutoff = 5
testthat::expect_equal(
object = healthiar::get_risk(
exp = 20,
cutoff = 5,
rr = 1.08,
rr_increment = 10,
erf_shape = "log_linear"
) |> base::round(x = _, digits = 4),
expected =
1.1224
)
## exp = 15, cutoff = 5
testthat::expect_equal(
object = healthiar::get_risk(
exp = 15,
cutoff = 5,
rr = 1.08,
rr_increment = 10,
erf_shape = "log_linear"
) |> base::round(x = _, digits = 4),
expected =
1.08
)
## exp = 5, cutoff = 5
testthat::expect_equal(
object = healthiar::get_risk(
exp = 5,
cutoff = 5,
rr = 1.08,
rr_increment = 10,
erf_shape = "log_linear"
) |> base::round(x = _, digits = 4),
expected =
1
)
## exp = 0, cutoff = 0
testthat::expect_equal(
object = healthiar::get_risk(
exp = 0,
cutoff = 0,
rr = 1.08,
rr_increment = 10,
erf_shape = "log_linear"
) |> base::round(x = _, digits = 4),
expected =
1
)
## exp = 0, cutoff = 5
testthat::expect_equal(
object = healthiar::get_risk(
exp = 0,
cutoff = 5,
rr = 1.08,
rr_increment = 10,
erf_shape = "log_linear"
) |> base::round(x = _, digits = 4),
expected =
1
)
}
)
## NOTE 2025-08-08: This example uses the log-log curve initially proposed by ChatGPT, which is not defined for exp = 0 or exp <= cutoff (that's why it's commented out); once we've settled on these new ERFs remove these error messages
# testthat::test_that("linear-log rescaling the same", {
# testthat::expect_equal(
# object = healthiar::get_risk(
# exp = 20,
# cutoff = 5,
# rr = 1.08,
# rr_increment = 10,
# erf_shape = "log_log"
# ) |> base::round(x = _, digits = 4),
# expected =
# 1.0941 # Results on 06 August 2024 (ChatGPT); no comparison study
# )
# }
# )
## This example uses the adapted lin-log curve (adapted based on the on the Pozzer 2022 (http://doi.org/10.1029/2022GH000711) log-log ERF)
testthat::test_that("linear-log rescaling the same", {
## exp = 20, cutoff = 5
testthat::expect_equal(
object = healthiar::get_risk(
exp = 20,
cutoff = 5,
rr = 1.08,
rr_increment = 10,
erf_shape = "linear_log"
),
expected =
1.102179903 # Results on 08 August 2024 (ChatGPT); no comparison study
)
## exp = 15, cutoff = 5
testthat::expect_equal(
object = healthiar::get_risk(
exp = 15,
cutoff = 5,
rr = 1.08,
rr_increment = 10,
erf_shape = "linear_log"
),
expected =
1.08
)
## exp = 5, cutoff = 5
testthat::expect_equal(
object = healthiar::get_risk(
exp = 5,
cutoff = 5,
rr = 1.08,
rr_increment = 10,
erf_shape = "linear_log"
),
expected =
1
)
## exp = 0, cutoff = 5
testthat::expect_equal(
object = healthiar::get_risk(
exp = 5,
cutoff = 5,
rr = 1.08,
rr_increment = 10,
erf_shape = "linear_log"
),
expected =
1
)
## exp = 0, cutoff = 0
testthat::expect_equal(
object = healthiar::get_risk(
exp = 5,
cutoff = 5,
rr = 1.08,
rr_increment = 10,
erf_shape = "linear_log"
),
expected =
1
)
}
)
## This example uses the log-log curve based on Pozzer 2022 (http://doi.org/10.1029/2022GH000711)
testthat::test_that("log-log rescaling the same", {
## exp = 15
### because exp - cutoff = 15 - 5 = 10, the result matches exactly the rr value from the literature
testthat::expect_equal(
object = healthiar::get_risk(
exp = 15,
cutoff = 5,
rr = 1.08,
rr_increment = 10,
erf_shape = "log_log"
),
expected =
1.08 # Results on 08 August 2024 (ChatGPT); no comparison study
)
## exp = cutoff = 5
testthat::expect_equal(
object = healthiar::get_risk(
exp = 5,
cutoff = 5,
rr = 1.08,
rr_increment = 10,
erf_shape = "log_log"
),
expected =
1 # Results on 08 August 2024 (ChatGPT); no comparison study
)
## exp = 0, cutoff = 5
testthat::expect_equal(
object = healthiar::get_risk(
exp = 5,
cutoff = 5,
rr = 1.08,
rr_increment = 10,
erf_shape = "log_log"
),
expected =
1 # Results on 08 August 2024 (ChatGPT); no comparison study
)
## exp = 20
testthat::expect_equal(
object = healthiar::get_risk(
exp = 20,
cutoff = 5,
rr = 1.08,
rr_increment = 10,
erf_shape = "log_log"
),
expected =
1.103291954 # Results on 08 August 2024 (ChatGPT); no comparison study
)
## exp = 10
testthat::expect_equal(
object = healthiar::get_risk(
exp = 10,
cutoff = 5,
rr = 1.08,
rr_increment = 10,
erf_shape = "log_log"
),
expected =
1.048709767 # Results on 08 August 2024 (ChatGPT); no comparison study
)
## exp = 30
testthat::expect_equal(
object = healthiar::get_risk(
exp = 30,
cutoff = 5,
rr = 1.08,
rr_increment = 10,
erf_shape = "log_log"
),
expected =
1.13752842 # Results on 08 August 2024 (ChatGPT); no comparison study
)
}
)
## NOTE 2025-08-08: This example uses the log-log curve initially proposed by ChatGPT, which is not defined for exp = 0 or exp <= cutoff (that's why it's commented out); once we've settled on these new ERFs remove these error messages
# testthat::test_that("log-log rescaling the same", {
# testthat::expect_equal(
# object = healthiar::get_risk(
# exp = 20,
# cutoff = 5,
# rr = 1.08,
# rr_increment = 10,
# erf_shape = "log_log"
# ) |> base::round(x = _, digits = 4),
# expected =
# 1.0947 # Results on 06 August 2024 (ChatGPT); no comparison study
# )
# }
# )
testthat::test_that("log-log rescaling the same based on Lehtomäki et al.", {
data <- read.csv(testthat::test_path("data","HeliLog-logcurve.csv")) #Lehtomäki et al. 2024
testthat::expect_equal(
signif(healthiar::get_risk(
exp = rep(data$exposure, each = 3),
cutoff = 0,
rr = c(1.08,1.06,1.09), #actual-cause mortality was 1.08 (95%CI 1.06, 1.09) per 10 µg/m3 (Chen and Hoek 2020).
rr_increment = c(10),
erf_shape = "log_log"),5),
expected = c(matrix(c(data$RRcentral,data$RR.lower,data$RRupper), nrow = 3, byrow = TRUE)))
})
# ERROR OR WARNING ########
## ERROR #########
## WARNING #########
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