Description Usage Arguments Details Value See Also Examples
Returns overall percent correct for all heuristics. 1. Create predictions using predictPair for all row pairs for all fitted heuristics in the list. 2. Calculate percent correct for each heuristic. Assumes the heuristics passed in have already been fitted to training data and all have the same criterion column.
1 | percentCorrect(test_data, ...)
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test_data |
Data to try to predict. Must have same criterion column and cols_to_fit as the data heuristics were fit to. |
... |
One or more heuristics fitted to data, e.g. the output of ttbModel. |
In cases where a heuristic guesses (predictPair outputs 0), percentCorrect will use the expected value, so output will be deterministic and repeatable. That is, if 10 guesses happen across the data set, percentCorrect will always allocate 5 to 1 and 5 to -1.
A one-row data.frame of numbers from 0 to 100, the percent correc of each heuristic. Each column is named with the heuristic's class or the fit name.
percentCorrectList
for a version which takes a list of
heuristics.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 | df <- data.frame(y=c(30,20,10,5), name=c("a", "b", "c", "d"),
x1=c(1,1,0,0), x2=c(1,1,0,1))
ttb <- ttbModel(df, 1, c(3:4))
sing <- singleCueModel(df, 1, c(3:4))
percentCorrect(df, ttb, sing)
# ttbModel singleCueModel
# 1 0.75 0.8333333
# TTB gets 75% correct while single cue model gets 83%.
# Now repeatedly sample 2 rows of the data set and see how outcomes are
# affected, tracking with the fit_name.
set.seed(1) # If you want to reproduce the same output as below.
ttb1 <- ttbModel(df[sample(nrow(df), 2),], 1, c(3:4), fit_name="fit1")
ttb2 <- ttbModel(df[sample(nrow(df), 2),], 1, c(3:4), fit_name="fit2")
ttb3 <- ttbModel(df[sample(nrow(df), 2),], 1, c(3:4), fit_name="fit3")
percentCorrect(df, ttb1, ttb2, ttb3)
# fit1 fit2 fit3
# 1 0.8333333 0.75 0.75
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