is.ok: does a vector have the sum required to be a row or column of...
In magic: Create and Investigate Magic Squares
is.ok R Documentation
does a vector have the sum required to be a row or column of a
magic square?
Description
Returns TRUE if and only if sum(vec)==magic.constant(n,d=d))
Usage
is.ok(vec, n=length(vec), d=2)
Arguments
vec
Vector to be tested
n
Order of square or hypercube. Default assumes order is equal
to length of vec
d
Dimension of square or hypercube. Default of 2 corresponds to a square
Author(s)
Robin K. S. Hankin
Examples
is.ok(magic(5)[1,])
magic documentation built on Nov. 16, 2022, 9:06 a.m.
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| is.ok | R Documentation |
does a vector have the sum required to be a row or column of a magic square?
Description
Returns TRUE if and only if sum(vec)==magic.constant(n,d=d))
Usage
is.ok(vec, n=length(vec), d=2)
Arguments
vec |
Vector to be tested |
n |
Order of square or hypercube. Default assumes order is equal
to length of |
d |
Dimension of square or hypercube. Default of 2 corresponds to a square |
Author(s)
Robin K. S. Hankin
Examples
is.ok(magic(5)[1,])
R Package Documentation
Browse R Packages
We want your feedback!
Note that we can't provide technical support on individual packages. You should contact the package authors for that.
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