listcol_extract | R Documentation |
Creaes a new column in your dataframe based on a subset of list-column values following a certain patten. For example, this is useful if you have labels you always apply to a repository with a set structure, e.g. key-value pairs like "priority:high", "priority:medium", and "priority:low" or other structures like "engagement-team", "teaching-team", etc. This function could create a new variable (e.g. "priority", "team") with the values encoded within the labels.
listcol_extract(data, col_name, regex, new_col_name = NULL, keep_regex = FALSE)
data |
Dataframe containing a list column (e.g. an issues dataframe) |
col_name |
Character string containing column name of list column (e.g. |
regex |
Character string of regular expression to identify list items of interest (e.g. |
new_col_name |
Optional name of new column. Otherwise |
keep_regex |
Optional logical denoting whether to keep regex part of matched item in value. Defaults to |
This function works only if each observatino contains at most one instance of a given patterns. When multiple labels match the same pattern, one is returned at random.
Dataframe with new column taking values extracted from list column
## Not run:
issues <- get_issues(repo)
issues_df <- parse_issues(issues)
listcol_extract(issues_df, "labels_name", "-team$")
## End(Not run)
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