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# API functions for common constraint programming problems
# These examples are taken from https://github.com/MiniZinc/minizinc-examples.
#' @title knapsack problem
#' @description
#' Solve a simple knapsack problem (Goal is to maximize the profit)
#' @param n number of items
#' @param capacity total capacity of carrying weight
#' @param profit profit corresponding to each item
#' @param size weight/size of each item
#' @export
knapsack = function(n, capacity, profit, size){
knapsack_string =
"
int: n; % number of objects
set of int: OBJ = 1..n;
int: capacity;
array[OBJ] of int: profit;
array[OBJ] of int: size;
array[OBJ] of var int: x; % how many of each object
constraint forall(i in OBJ)(x[i] >= 0);
constraint sum(i in OBJ)(size[i] * x[i]) <= capacity;
solve maximize sum(i in OBJ)(profit[i] * x[i]);
"
model = suppressMessages(mzn_parse(model_string = knapsack_string))
# list of the data
pVals = list(Int$new(n), Int$new(capacity), Array$new(intExpressions(profit),
dimranges = list(IntSetVal$new(1, n)))
, Array$new(intExpressions(size),
dimranges = list(IntSetVal$new(1, n))))
names(pVals) = c("n", "capacity", "profit", "size")
# set the missing parameters
model = set_params(modData = pVals, model = model)
solutions = mzn_eval(r_model = model)
return(list(model = model, solution = solutions))
}
#' @title assignment problem 2
#' @description
#' Solve an assignment problem (Goal is to minimize the cost)
#' @param n number of agents
#' @param m number of tasks
#' @param cost m x n 2D array where each row corresponds to the cost of each task for that agent.
#' (to be provided as 1-D vector)
#' @export
assignment = function(n, m, cost){
assignment_string =
'
int: n;
set of int: DOM = 1..n;
int: m;
set of int: COD = 1..m;
array[DOM,COD] of int: cost;
array[DOM] of var COD: task;
include "alldifferent.mzn";
constraint alldifferent(task);
solve minimize sum(w in DOM)
(cost[w,task[w]]);
'
model = mzn_parse(model_string = assignment_string)
# list of the data
pVals = list(Int$new(n), Int$new(m),
Array$new(exprVec = intExpressions(cost),
dimranges = list(IntSetVal$new(1,n), IntSetVal$new(1,m))))
names(pVals) = c("n", "m", "cost")
# set the missing parameters
model = set_params(modData = pVals, model = model)
solutions = mzn_eval(r_model = model)
return(list(model = model, solution = solutions))
}
#' @title assignment problem 2
#' @description
#' Solve an assignment problem
#' Winston "Operations Research", page 398, swimming team example
#' Model created by Hakan Kjellerstrand(hakank(at)bonetmail.com)
#' See : http://www.hakank.org/minizinc/assignment2.mzn
#' @param rows number of columns
#' @param cols number of tasks
#' @param cost cost matrix (to be provided as 1-D vector)
#' @export
assignment_2 = function(rows, cols, cost){
model_string =
"
predicate assignment(array[int, int] of var 0..1: x,
array[int, int] of int: cost,
var int: s
) =
forall(i in index_set_1of2(x)) (sum(j in index_set_2of2(x)) (x[i,j]) = 1) /\\
if card(index_set_1of2(x)) = card(index_set_2of2(x)) then
forall(j in index_set_2of2(x)) (sum(i in index_set_1of2(x)) (x[i,j]) = 1)
else
forall(j in index_set_2of2(x)) (sum(i in index_set_1of2(x)) (x[i,j]) <= 1)
endif
/\\
s = sum(i in index_set_1of2(x), j in index_set_2of2(x)) (x[i,j]*cost[i,j])
;
int: rows;
int: cols;
array[1..rows, 1..cols] of var 0..1: x;
array[1..rows, 1..cols] of int: cost;
var int: total_sum;
solve minimize total_sum;
constraint
assignment(x, cost, total_sum)
% /\\ total_sum <= 181
;
"
model = mzn_parse(model_string = model_string)
# list of the data
pVals = list(Int$new(rows), Int$new(cols),
Array$new(exprVec = intExpressions(cost),
dimranges = list(IntSetVal$new(1,rows), IntSetVal$new(1,cols))))
names(pVals) = c("rows", "cols", "cost")
# set the missing parameters
model = set_params(modData = pVals, model = model)
solutions = mzn_eval(r_model = model)
return(list(model = model, solution = solutions))
}
#' @title magic squares problem
#' @description
#' Solve a magic squares problem in MiniZinc
#' Model created by Hakan Kjellerstrand(hakank(at)bonetmail.com)
#' See : http://www.hakank.org/minizinc/magic_square.mzn
#' @param n order of magic square
#' @export
magic_square = function(n){
model_string =
'
include "globals.mzn";
int: n;
int: total = ( n * (n*n + 1)) div 2;
% var 0..n*n*n: total;
array[1..n,1..n] of var 1..n*n: magic;
% solve satisfy;
solve :: int_search(
[magic[i,j] | i in 1..n, j in 1..n],
first_fail,
indomain_random, % indomain_median,
complete)
satisfy;
constraint
all_different([magic[i,j] | i in 1..n, j in 1..n]) % :: bounds % domain
/\\
forall(k in 1..n) (
sum(i in 1..n) (magic[k,i]) = total /\\
sum(i in 1..n) (magic[i,k]) = total
)
/\\ % diagonal
sum(i in 1..n) (magic[i,i]) = total
/\\ % diagonal
sum(i in 1..n) (magic[i,n-i+1]) = total
/\\ total = ( n * (n*n + 1)) div 2
;
'
model = mzn_parse(model_string = model_string)
# list of the data
pVals = list(Int$new(n))
names(pVals) = c("n")
# set the missing parameters
model = set_params(modData = pVals, model = model)
solutions = mzn_eval(r_model = model)
return(list(model = model, solution = solutions))
}
#' @title magic series problem
#' @description
#' Solve a magic series problem in MiniZinc
#' Model created by Hakan Kjellerstrand(hakank(at)bonetmail.com)
#' See : http://www.hakank.org/minizinc/magic_series.mzn
#' @param n order of magic square
#' @export
magic_series = function(n){
model_string =
'
include "globals.mzn";
int: n;
int: n2 = n*n;
int: m = n*(n2+1);
% decision variables
array[1..n] of var 1..n2: x;
% solve satisfy;
solve :: int_search(x, first_fail, indomain_min, complete) satisfy;
constraint
sum(x)*2 = m /\\
all_different(x) /\\
increasing(x)
;
'
model = mzn_parse(model_string = model_string)
# list of the data
pVals = list(Int$new(n))
names(pVals) = c("n")
# set the missing parameters
model = set_params(modData = pVals, model = model)
solutions = mzn_eval(r_model = model)
return(list(model = model, solution = solutions))
}
#' @title production planning problem
#' @description
#' simple production planning problem taken from
#' https://github.com/MiniZinc/minizinc-examples
#' Goal is to maximize the profit
#' @param nproducts number of different products
#' @param profit profit for each product (1-D vector)
#' @param pnames names of each product (1-D vector)
#' @param nresources number of resources
#' @param capacity amount of each resource available (1-D vector)
#' @param rnames names of each resource (1-D vector)
#' @param consumption units of each resource required to produce
#' 1 unit of product (2-D vector to be provided as 1-D vector)
#' @export
production_planning = function(nproducts, profit, pnames, nresources,
capacity, rnames, consumption){
model_string =
'
% Number of different products
int: nproducts;
set of int: Products = 1..nproducts;
%profit per unit for each product
array[Products] of int: profit;
array[Products] of string: pname;
%Number of resources
int: nresources;
set of int: Resources = 1..nresources;
%amount of each resource available
array[Resources] of int: capacity;
array[Resources] of string: rname;
%units of each resource required to produce 1 unit of product
array[Products, Resources] of int: consumption;
constraint assert(forall (r in Resources, p in Products)
(consumption[p,r] >= 0), "Error: negative consumption");
% bound on number of Products
int: mproducts = max (p in Products)
(min (r in Resources where consumption[p,r] > 0)
(capacity[r] div consumption[p,r]));
% Variables: how much should we make of each product
array[Products] of var 0..mproducts: produce;
array[Resources] of var 0..max(capacity): used;
% Production cannot use more than the available Resources:
constraint forall (r in Resources) (
used[r] = sum (p in Products)(consumption[p, r] * produce[p])
/\\ used[r] <= capacity[r]
);
% Maximize profit
solve maximize sum (p in Products) (profit[p]*produce[p]);
'
model = mzn_parse(model_string = model_string)
if(length(profit) != nproducts || length(pnames) != nproducts){
stop("length of profit and/or pnames must be equal to nproducts")
}
if(length(capacity) != nresources || length(rnames) != nresources){
stop("length of capacity and/or names must be equal to nresources")
}
if(length(consumption) != nproducts*nresources){
stop("length of consumption must be equal to nproducts*nresources")
}
# list of the data
pVals = list(Int$new(nproducts),
Array$new(exprVec = intExpressions(profit), dimranges = list(IntSetVal$new(1, nproducts))),
Array$new(exprVec = stringExpressions(pnames), list(IntSetVal$new(1, nproducts))),
Int$new(nresources),
Array$new(exprVec = intExpressions(capacity), dimranges = list(IntSetVal$new(1, nresources))),
Array$new(exprVec = stringExpressions(rnames), list(IntSetVal$new(1, nresources))),
Array$new(exprVec = intExpressions(consumption), dimranges = list(IntSetVal$new(1, nproducts),
IntSetVal$new(1, nresources))))
names(pVals) = c("nproducts", "profit", "pname", "nresources",
"capacity", "rname", "consumption")
# set the missing parameters
model = set_params(modData = pVals, model = model)
solutions = mzn_eval(r_model = model)
return(list(model = model, solution = solutions))
}
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