Show that the points (4, 6), (-1, 5), (-2, 0), (3, 1) are the vertices of a rhombus. Question Show that the points (4, 6), (-1, 5), (-2, 0), (3,1) are the vertices of a rhombus. in progress 0 Math Gianna 1 month 2021-09-09T09:00:58+00:00 2021-09-09T09:00:58+00:00 1 Answer 0

## Answers ( )

Answer:|AB|=|BC|=|CD|=|DA|=√26

This shows that the points are vertices of a rhombus.

Step-by-step explanation:Show that the points (4, 6), (-1, 5), (-2, 0), (3,

1) are the vertices of a rhombus, we simply have to show that they all have equal distances.

Let ABCD be the vertices of the rhombus (4, 6), (-1, 5), (-2, 0), (3,

1) respectively. That is;

A(4, 6), B(-1, 5), C(-2, 0), D(3,

1)

We will find the distance AB, BC, CD and DA, If the distances between them are equal, then we are able to prove that it is a rhombus;

Using the distance formula;

D = √( – )² + ( – )²

Distance AB

A(4, 6), B(-1, 5)

=4 =6 =-1 =5

|AB|=√( – )² + ( – )²

=√(5- 6)² + (-1- 4)²

=√(-1)² + (-5)²

=√1+ 25

=√26

Distance BC

B(-1, 5), C(-2, 0)

=-1 =5 =-2 =0

|BC|=√( – )² + ( – )²

=√(0 – 5)² + (-2+1)²

=√(-5)² + (-1)²

=√25+1

=√26

Distance CD

C(-2, 0), D(3,

1)

=-2 =0 =3 =1

|CD|=√( – )² + ( – )²

=√(1 – 0)² + (3+2)²

=√(1)² + (5)²

=√1+25

=√26

Distance DA

D(3,

1) A(4,6)

=3 =1 =4 =6

|DA|=√( – )² + ( – )²

=√(6 – 1)² + (4-3)²

=√(5)² + (1)²

=√25+1

=√26

|AB|=|BC|=|CD|=|DA|=√26

This shows that the points are vertices of a rhombus.