parser_1: [!] Parse a filename

In GegznaV/spHelper: Extension of Package `hyperSpec` and Various Convenience Functions

[!] Parse a filename

Description

Parse a string with filename and return a dataframe with extracted information.

Usage

parser_1(x)

Arguments

x

A sting.

Details

Is x is a filename with a path, only the filename without path is parsed.

Value

A data frame.

Examples

string <- "aliejus;silicis;0.5mW;1;NA;_RamanShift_14-51-36-968.txt"
parser_1(string)

string3 <- c(string,string,string)
parser_1(string3)

GegznaV/spHelper documentation built on April 16, 2023, 1:42 p.m.