normalizeDifferencesToAverage | R Documentation |
Rescales channel vectors to get the same average.
## S3 method for class 'list'
normalizeDifferencesToAverage(x, baseline=1, FUN=median, ...)
x |
A |
baseline |
An |
FUN |
A |
... |
Additional arguments passed to the |
Returns a normalized list
of length K.
Henrik Bengtsson
# Simulate three shifted tracks of different lengths with same profiles
ns <- c(A=2, B=1, C=0.25)*1000
xx <- lapply(ns, FUN=function(n) { seq(from=1, to=max(ns), length.out=n) })
zz <- mapply(seq_along(ns), ns, FUN=function(z,n) rep(z,n))
yy <- list(
A = rnorm(ns["A"], mean=0, sd=0.5),
B = rnorm(ns["B"], mean=5, sd=0.4),
C = rnorm(ns["C"], mean=-5, sd=1.1)
)
yy <- lapply(yy, FUN=function(y) {
n <- length(y)
y[1:(n/2)] <- y[1:(n/2)] + 2
y[1:(n/4)] <- y[1:(n/4)] - 4
y
})
# Shift all tracks toward the first track
yyN <- normalizeDifferencesToAverage(yy, baseline=1)
# The baseline channel is not changed
stopifnot(identical(yy[[1]], yyN[[1]]))
# Get the estimated parameters
fit <- attr(yyN, "fit")
# Plot the tracks
layout(matrix(1:2, ncol=1))
x <- unlist(xx)
col <- unlist(zz)
y <- unlist(yy)
yN <- unlist(yyN)
plot(x, y, col=col, ylim=c(-10,10))
plot(x, yN, col=col, ylim=c(-10,10))
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