#' Return total blup of breedR
#'
#' @description
#' \code{cnj_recode} Return CNJ
#' @param mod: cnj_recode
#'
#' @examples
#' date = c("2019-03-20","2018-05-12","2019-11-06","2020-01-23","2020-04-03")
#' date
#' cnj_recode(date)
cnj_recode <- function(date){
# 12,1,2月是前一年的4季度
# 3,4,5是本年的第一季度
# 6,7,8是本年的第二季度
# 9,10,11是本年的第三季度,以此类推进行编码
## 这里生成从1800年到2800年一千年的转换
require(lubridate)
total = as.Date("1899-11-01")+months(1:12003)
total1 = as.character(total,format = "%Y%m")
mubiao = paste0(c(1899,1899,1899,rep(1900:2899,each=12)),rep(rep(c(4,1,2,3),each=3),100))
dd = data.frame(ID = total1,mubiao = mubiao)
result = as.character(as.Date(date),format = "%Y%m")
re = dd[match(result,dd$ID),2] # 不能用 %in% ,顺序会变化,要用match才可以
return(re)
}
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