GetDayLength: Get the day length

Usage Arguments Examples

Usage

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GetDayLength(Lat, month, dayofyear = c(Jan = 16, Feb = 44, Mar = 75, Apr = 105, May = 136, Jun = 166, Jul = 197, Aug = 228, Sep = 258, Oct = 289, Nov = 319, Dec = 350))

Arguments

Lat
month
dayofyear

Examples

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##---- Should be DIRECTLY executable !! ----
##-- ==>  Define data, use random,
##--	or do  help(data=index)  for the standard data sets.

## The function is currently defined as
function (Lat, month, dayofyear = c(Jan = 16, Feb = 44, Mar = 75, 
    Apr = 105, May = 136, Jun = 166, Jul = 197, Aug = 228, Sep = 258, 
    Oct = 289, Nov = 319, Dec = 350)) 
{
    SLAt <- sin(pi * Lat/180)
    cLat <- cos(pi * Lat/180)
    sinDec <- 0.4 * sin(0.0172 * (dayofyear[month] - 80))
    cosH0 <- -sinDec * SLAt/(cLat * sqrt(1 - sinDec^2))
    if (cosH0 > 1) {
        fDayLength <- 0
    }
    else if (cosH0 < -1) {
        fDayLength <- 1
    }
    else {
        fDayLength <- acos(cosH0)/pi
    }
    daylength <- fDayLength * 86400
    return(daylength)
  }

drGeorgeXenakis/fr3PGD documentation built on June 3, 2020, 6:10 a.m.