PairSharedQuartetStatus | R Documentation |
Removes all tips that do not occur in both tree1
and tree2
, then calculates
the status of the remaining quartets.
PairSharedQuartetStatus(tree1, tree2)
tree1 , tree2 |
Trees of class |
Returns a named array of six integers corresponding to the quantities of Estabrook et al. (1985):
The total number of quartet statements for two trees of n leaves, i.e. 2 Q.
The total number of quartets for n leaves.
The number of quartets that are resolved identically in both trees.
The number of quartets that are resolved differently in each tree.
The number of quartets that are resolved in tree 1, but not in tree 2.
The number of quartets that are resolved in tree 2, but not in tree 1.
The number of quartets that are unresolved in both trees.
Martin R. Smith (martin.smith@durham.ac.uk)
Other element-by-element comparisons:
CompareQuartets()
,
CompareQuartetsMulti()
,
CompareSplits()
,
QuartetState()
,
SharedQuartetStatus()
,
SplitStatus()
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