r i = {{i}}
r vars[i]
# Check design lc <- ck.rcbd(dfr, vars[i], trt, rep) # Fit a model for assumptions plots model <- aov(dfr[, vars[i]] ~ dfr[, trt] + dfr[, rep]) # Estimate missing values y.est <- paste0(vars[i], ".est") if (lc$nmis > 0) { dfr[, y.est] <- mve.rcbd(dfr, vars[i], trt, rep, maxp)[, y.est] } else { dfr[, y.est] <- dfr[, vars[i]] } # Get anova table with estimated missing values at <- suppressWarnings(aov.rcbd(dfr, vars[i], trt, rep, maxp)) # CV cv <- (at[3, 3])^0.5 / mean(dfr[, y.est]) * 100 # ANOVA with subsampling show.anova.sub <- FALSE if (!is.null(eu)) if (sum(is.na(dfr2[, vars[i]])) == 0 & dim(dfr)[1] < dim(dfr2)[1]) { model2 <- aov(dfr2[, vars[i]] ~ dfr2[, trt] + dfr2[, rep] + dfr2[, eu] %in% dfr2[, trt]) model2$terms[[2]] <- vars[i] at2 <- anova(model2) at2[1, 4] <- at2[1, 3] / at2[3, 3] at2[2, 4] <- at2[2, 3] / at2[3, 3] at2[1, 5] <- pf(at2[1, 4], at2[1, 1], at2[3, 1], lower.tail = FALSE) at2[2, 5] <- pf(at2[2, 4], at2[2, 1], at2[3, 1], lower.tail = FALSE) rownames(at2) <- c(trt, rep, "Exp. Error", "Sampling Error") show.anova.sub <- TRUE }
It is always good to have some visualization of your data. Below a histogram and a boxplot are shown.
par(mfrow = c(1, 2)) hist(dfr[, vars[i]], main = paste("Histogram of", vars[i]), xlab = vars[i]) boxplot(dfr[, vars[i]], ylab = vars[i])
r if(lc$ng < 10) {paste0(" Since the number of " , trt.lab.s, " in your experiment is not so large, we can plot the data for each ", trt.lab, ":")}
if (lc$ng < 10) msdplot(dfr, vars[i], trt, conf = 1, pch = 4)
You have fitted a linear model for a RCBD. The ANOVA table for your model is:
at
r if(lc$nmis > 0) paste0("You have some missing values (", format(lc$pmis * 100, digits = 3), "%) and they have been estimated before running ANOVA.")
The coefficient of variation for this experiment is r format(cv, digits = 4)
%.
The p-value for r trt.lab.s
is r format(at[1, 5], digits = 4)
r if(at[1, 5] < 0.05) {"which is significant at the 5% level."} else {"which is not significant at the 5% level."}
r if(show.anova.sub) {"At the subsample level, the ANOVA table is:"}
if (show.anova.sub)
at2
r if(show.anova.sub) {if (at2[3, 5] > 0.05) {"The p-value for the experimental error is non-significant which implies that plot to plot variation is low. Thus, fewer plots with more subsamples could be used."}}
r if(show.anova.sub) {if (at2[3, 5] < 0.05) {"The p-value for the experimental error is significant which implies that plot to plot variation is high. Thus, more plots could be used."}}
Don't forget the assumptions of the model. It is supposed that the errors are independent with a normal distribution and with the same variance for all the r trt.lab.s
. The following plots can help you evaluate this:
par(mfrow = c(1, 2)) plot(model, which = 1) plot(model, which = 2)
Any trend in the residuals in the left plot would violate the assumption of independence while a trend in the variability of the residuals --for instance a funnel shape-- suggests heterogeneity of variances. Departures from the theoretical normal line on the right plot are symptoms of lack of normality.
r trt.lab.c
meansr if(at[1, 5] < 0.05 | mc) {paste("Below are the sorted means for each", trt.lab, "using the Fisher's Least Significant Difference method and the multiple comparisons method of Tukey, both at the 5% level. Letters indicate if there are significant differences.")} else {paste("Because the effect of", trt.lab.s, "was not significant in the ANOVA, multiple comparison tests are not presented. The means of your", trt.lab.s, "are:")}
r if (at[1, 5] < 0.05 | mc) {paste0("### ", {{i+1}}, ".4.1. LSD test")}
if (at[1, 5] < 0.05 | mc) { means <- dfr[, y.est] agricolae::LSD.test(means, dfr[, trt], at[3, 1], at[3, 3])$groups }
r if (at[1, 5] < 0.05 | mc) {paste0("### ", {{i+1}}, ".4.2. Tukey test")}
if (at[1, 5] < 0.05 | mc) agricolae::HSD.test(means, dfr[, trt], at[3, 1], at[3, 3])$groups
if (at[1, 5] > 0.05 & !mc) tapply(dfr[, y.est], dfr[, trt], mean)
Below are the variance components for this model, under the assumption that r trt.lab.s
and blocks are random. Here the model is fitted using REML and missing values are not estimated.
y <- dfr[, vars[i]] fg <- dfr[, trt] fr <- dfr[, rep] ff <- as.formula(y ~ (1|fg) + (1|fr)) model <- lme4::lmer(ff) vc <- data.frame(lme4::VarCorr(model)) vc[vc[, 1] == "fg", 1] <- trt vc[vc[, 1] == "fr", 1] <- rep rownames(vc) <- vc[, 1] vc <- vc[, c(4, 5)] colnames(vc) <- c("Variance", "Std.Dev.") vc
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