subst.expr: Substitute some pattern by a list of alternatives
In skranz/sktools: Helpful functions used in my courses
Description
Substitute some pattern by a list of alternatives
Usage
1
subst.expr(expr.str, subst, collapse = ",", add.list = FALSE)
Examples
1
2
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4
## Not run:
subst.expr("mean.ATTR=mean(ATTR)",subst=list(ATTR=c("hp","li")))
## End(Not run)
skranz/sktools documentation built on April 12, 2021, 11:43 a.m.
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Description
Substitute some pattern by a list of alternatives
Usage
1 | subst.expr(expr.str, subst, collapse = ",", add.list = FALSE)
|
Examples
1 2 3 4 | ## Not run:
subst.expr("mean.ATTR=mean(ATTR)",subst=list(ATTR=c("hp","li")))
## End(Not run)
|
R Package Documentation
Browse R Packages
We want your feedback!
Note that we can't provide technical support on individual packages. You should contact the package authors for that.
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