View source: R/apply_decision_rules.R
apply_decision_rules | R Documentation |
This function defines and applies some decision rules to assess emerging status at a specific time.
apply_decision_rules(
df,
y_var = "ncells",
eval_year,
year = "year",
taxonKey = "taxonKey"
)
df |
df. A dataframe containing temporal data of one or more taxa. The column with taxa can be of class character, numeric or integers. |
y_var |
character. Name of column of |
eval_year |
numeric. Temporal value at which emerging status has to be
evaluated. |
year |
character. Name of column of |
taxonKey |
character. Name of column of |
Based on the decision rules output we define the emergency status value,
em
:
dr_3
is TRUE
: em = 0
(not emerging)
dr_1
and dr_3
are FALSE
, dr_2
and dr_4
are TRUE
: em = 3
(emerging)
dr_2
is TRUE
, all others are FALSE
: em = 2
(potentially emerging
(dr_1
is TRUE
and dr_3
is FALSE
) or (dr_1
, dr_2
and dr_3
are
FALSE
): em = 1
(unclear)
df. A dataframe (tibble) containing emerging status. Columns:
taxonKey
: column containing taxon ID. Column name
equal to value of argument taxonKey
.
year
: column
containing temporal values. Column name equal to value of argument
year
. Column itself is equal to value of argument eval_year
.
So, if you apply decision rules on years 2018 (eval_year = 2018
),
you will get 2018 in this column.
em_status
: numeric.
Emerging status, an integer between 0 and 3, based on output of decision
rules (next columns). See details for more information.
dr_1
: logical. Output of decision rule
1 answers to the question: does the time series contain only one positive
value at evaluation year?
dr_2
: logical. Output of decision
rule 2 answers to the question: is value at evaluation year above median
value?
dr_3
: logical. Output of decision rule 3 answers to
the question: does the time series contains only zeros in the five years
before eval_year
?
dr_4
: logical. Output of decision
rule 4 answers to the question: is the value in column y_var
the
maximum ever observed up to eval_year
?
df <- dplyr::tibble(
taxonID = c(rep(1008955, 10), rep(2493598, 3)),
y = c(seq(2009, 2018), seq(2016, 2018)),
obs = c(1, 0, 1, 1, 0, 0, 0, 0, 0, 0, 1, 3, 0)
)
apply_decision_rules(df,
eval_year = 2016,
y_var = "obs",
taxonKey = "taxonID",
year = "y"
)
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