Description Usage Arguments Value Author(s) Examples
Calculate the Stationary Distribution of Markov Chain
1 2 3 4 |
obj |
the Markov Chain we want to apply |
k |
for infinite state Markov Chain, the initial state to do the iterative process in order to find the stationary distribution, default value is 10 |
ending |
for infinite state Markov Chain, the ending criterion of the iterative process, default value is 10 |
epsilon |
for infinite state Markov Chain, the convergence criterion to stop the iterative process, default value is 0.05 |
A matrix corresponding to the stationary states
Jiexuan Cao, Yuki Liu, Qianhan Zhang
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 | #discrete finite state markov chain
dtftmc = mc(states = c("sunny", "cloudy", "rain"),
pijdef = function(i,j,...) {
if (i == 1 && j < 3 ||
i == 2 && j != 2 ||
i == 3 && j > 1) return(0.5)
0
},
name = "Weather")
dtftsd = stn(dtftmc)
pijdeffunction = function(i,j) {
p = 0.3
q = 0.7
r = 0
if (i == 1 && j == 1)
return (1 - p)
if(j == i + 1)
return(p)
if(j == i - 1)
return(q)
if(j==i)
return(r)
return(0)
}
dtiftmc = mc(states = "infinity",
pijdef = pijdeffunction,
name = "death and birth")
dtiftsd = stn(dtiftmc, ending = 20)
#continuous finite state markov chain
ctftmc = mc(states = c("0", "1", "2"),
pijdef = matrix(c(0, 0.2857143, 0, 1, 0, 1, 0, 0.7142857, 0), ncol = 3),
qidef = c(0.25, 0.175, 0.08),
name = 'Machine Repair')
stn(ctftmc)
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