Description Usage Arguments Details Value Author(s) References Examples
Estimate adpative index model for binary outcomes in the context of logistic regression. The resulting index characterizes the main covariate effect on the response probability.
1 | logistic.main(x, y, nsteps=8, mincut=.1, backfit=F, maxnumcut=1, dirp=0, weight=1)
|
x |
n by p matrix. The covariate matrix |
y |
n 0/1 vector. The binary response variable |
nsteps |
the maximum number of binary rules to be included in the index |
backfit |
T/F. Whether the existing split points are adjusted after including a new binary rule |
mincut |
The minimum cutting proportion for the binary rule at either end. It typically is between 0 and 0.2. |
maxnumcut |
The maximum number of binary splits per predictor |
dirp |
p vector. The given direction of the binary split for each of the p predictors. 0 represents "no pre-given direction"; 1 represents "(x>cut)"; -1 represents "(x<cut)". Alternatively, "dirp=0" represents that there is no pre-given direction for any of the predictor. |
weight |
a positive number. The weight given to responses. "weight=0" means that all observations are equally weighted. |
logistic.main
sequentially estimates a sequence of adaptive index models with up to "nsteps" terms for binary outcomes. The appropriate number of binary rules can be selected via K-fold cross-validation(cv.logistic.main
).
logistic.main
returns maxsc
, which is the score test statistics achieved in the fitted model and res
, which is a list with components
jmaa |
number of predictors |
cutp |
split points for the binary rules |
maxdir |
direction of split: 1 represents "(x>cut)" and -1 represents "(x<cut)" |
maxsc |
observed score test statistics for the main effect |
Lu Tian and Robert Tibshirani
Lu Tian and Robert Tibshirani (2010) "Adaptive index models for marker-based risk stratification", Tech Report, available at http://www-stat.stanford.edu/~tibs/AIM.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 | ## generate data
set.seed(1)
n=200
p=10
x=matrix(rnorm(n*p), n, p)
z=(x[,1]<0.2)+(x[,5]>0.2)
beta=1
prb=1/(1+exp(-beta*z))
y=rbinom(n,1,prb)
## fit logistic main effects AIM
a=logistic.main(x, y, nsteps=10)
## examine the model sequence
print(a)
## compute the index based on the 2nd model of the sequence using data x
z.prd=index.prediction(a$res[[2]],x)
## compute the index based on the 2nd model of the sequence using new data xx, and compare the result with the true index
nn=10
xx=matrix(rnorm(nn*p), nn, p)
zz=(xx[,1]<0.2)+(xx[,5]>0.2)
zz.prd=index.prediction(a$res[[2]],xx)
cbind(zz, zz.prd)
|
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