s: Subtraction of two LR fuzzy numbers In Calculator.LR.FNs: Calculator for LR Fuzzy Numbers

Description

This function calculates subtraction (difference) of two fuzzy numbers M=(m, α, β)_{LR} and N=(n, γ, δ)_{RL} on the basis of Zadeh extension principle by the following formula:

M \ominus N = (m-n, α+δ, β+γ)_{LR}

Usage

 1 s(M, N)

Arguments

 M The first LR (or RL or L) fuzzy number N The second LR (or RL or L) fuzzy number

Value

A LR (or RL or L) fuzzy number

Abbas Parchami

References

Dubois, D., Prade, H., Fuzzy Sets and Systems: Theory and Applications. Academic Press (1980).

Dubois, D., Prade, H., Operations on fuzzy numbers. International Journal of Systems Science 9 (1978), 613-626.

Dubois, D., Prade, H., Fuzzy numbers: An overview. In In: Analysis of Fuzzy Information. Mathematical Logic, Vol. I. CRC Press (1987), 3-39.

Dubois, D., Prade, H., The mean value of a fuzzy number. Fuzzy Sets and Systems 24 (1987), 279-300.

Kaufmann, A., Gupta, M.M., Introduction to Fuzzy Arithmetic. van Nostrand Reinhold Company, New York (1985).

Taheri, S.M, Mashinchi, M., Introduction to Fuzzy Probability and Statistics. Shahid Bahonar University of Kerman Publications, In Persian (2009).

Viertl, R., Statistical Methods for Fuzzy Data. John Wiley & Sons, Chichester (2011).

Zadeh, L.A., The concept of a linguistic variable and its application to approximate reasoning-I. Information Sciences 8 (1975), 199-249.

Examples

 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 # Example 1: Left.fun = function(x) { (1/(1+x^2))*(x>=0)} Right.fun = function(x) { (1/(1+(2*abs(x))))*(x>=0)} M = LR(1, 0.6, 0.2) N = RL(3, 0.5, 1) s(N, M) s(M, N) s(M, M) s(s(N, M), M) # Example 2: Left.fun = function(x) { (1-x)*(x>=0)} A = L(5,3,2) B = L(3,2,1) LRFN.plot( A, xlim=c(-3,12), lwd=2, lty=2, col=2) LRFN.plot( B, lwd=2, lty=2, col=3, add=TRUE) LRFN.plot( s(A, B), lwd=2, lty=3, col=1, add=TRUE) legend( "topright", c("A = L(5, 3, 2)", "B = L(3, 2, 1)", "A - B = L(2, 4, 4)"), col = c(2, 3, 1) , text.col = 1, lwd = c(2,2,2), lty = c(2, 2, 3) ) ## The function is currently defined as function (M, N) { options(warn = -1) if (messages(M) != 1) { return(messages(M)) } if (messages(N) != 1) { return(messages(N)) } if ((M == 1 & N == 0) | (M == 0 & N == 1) | (M == 0.5 & N == 0.5)) { a1 = M - N a2 = M + N a3 = M + N a4 = M print(noquote(paste0("the result of subtraction is (core = ", a1, ", left spread = ", a2, ", right spread = ", a3, ")", if (a4 == 0) { paste0(" LR") } else if (a4 == 1) { paste0(" RL") } else { paste0(" L") }))) return(invisible(c(a1, a2, a3, a4))) } else { return(noquote(paste0( "Subtraction has NOT a closed form of a LR fuzzy number" ))) } }

Example output Attaching package: 'Calculator.LR.FNs'

The following object is masked from 'package:base':

sign

 the result of subtraction is  (core = 2, left spread = 0.7, right spread = 1.6) RL
 the result of subtraction is  (core = -2, left spread = 1.6, right spread = 0.7) LR
 Subtraction has NOT a closed form of a LR fuzzy number
 the result of subtraction is  (core = 2, left spread = 0.7, right spread = 1.6) RL
 the result of subtraction is  (core = 1, left spread = 0.9, right spread = 2.2) RL
 the result of subtraction is  (core = 2, left spread = 4, right spread = 4) L
function (M, N)
{
options(warn = -1)
if (messages(M) != 1) {
return(messages(M))
}
if (messages(N) != 1) {
return(messages(N))
}
if ((M == 1 & N == 0) | (M == 0 & N == 1) | (M ==
0.5 & N == 0.5)) {
a1 = M - N
a2 = M + N
a3 = M + N
a4 = M
print(noquote(paste0("the result of subtraction is  (core = ",
a1, ", left spread = ", a2, ", right spread = ",
a3, ")", if (a4 == 0) {
paste0(" LR")
}
else if (a4 == 1) {
paste0(" RL")
}
else {
paste0(" L")
})))
return(invisible(c(a1, a2, a3, a4)))
}
else {
return(noquote(paste0("Subtraction has NOT a closed form of a LR fuzzy number")))
}
}

Calculator.LR.FNs documentation built on May 2, 2019, 8:25 a.m.