Nothing
# Testing cohorts with one overlap ---------------------------
target <- c("AA B")
cohort <- c("AA B", "AA C", "AA D CC", "AA EE CC DD")
non_matches <- c("A", "A B", "B", "CC AA B")
lexicon <- Reduce(
union,
list(
cohort,
non_matches
)
)
test_that("two phone cohort are correct", {
expect_setequal(lexicon[get_cohorts(target, lexicon, overlap = 1)], cohort)
})
target <- c("AA")
cohort <- c("AA")
non_matches <- c("AAA B", "AAA B CC", "B", "B AA", "B AA CC", "A")
lexicon <- Reduce(
union,
list(
cohort,
non_matches
)
)
test_that("two character and one phone cohort with one overlap are correct", {
expect_setequal(lexicon[get_cohorts(target, lexicon, overlap = 1)], cohort)
})
target <- c("A")
cohort <- c("A")
non_matches <- c("AA", "AA B", "AA B CC", "B", "B AA", "B AA CC")
lexicon <- Reduce(
union,
list(
cohort,
non_matches
)
)
test_that("one character and one phone cohort with one overlap are correct", {
expect_setequal(lexicon[get_cohorts(target, lexicon, overlap = 1)], cohort)
})
# Testing rhymes third onset ---------------------------
target <- c("AA B C")
rhyme <- c("C", "B C", "AA B C", "AA BB C", "DD B C", "A AA B C", "D AA B C", "E D AA B C")
non_matches <- c("A B", "AA B", "CC", "AA B CC", "AA B C D", "EE AA B C D")
lexicon <- Reduce(
union,
list(
rhyme,
non_matches
)
)
test_that("three phone rhyme third onset is correct", {
expect_setequal(lexicon[get_rhymes(target, lexicon, mismatch = 2)], rhyme)
})
target <- c("AA")
rhyme <- c("C B AA", "B AA", "AA")
non_matches <- c("A", "BB", "AA BB", "C AA B", "B A")
lexicon <- Reduce(
union,
list(
rhyme,
non_matches
)
)
test_that("one phone rhyme third onset is correct", {
expect_setequal(lexicon[get_rhymes(target, lexicon, mismatch = 2)], rhyme)
})
target <- c("AA B")
rhyme <- c("B", "AA B", "DD B", "D AA B", "C D AA B")
non_matches <- c("A", "AA", "BB", "AA BB", "AA CC", "AA B CC", "C D AAA B", "C D AAA BB", "C D AA E")
lexicon <- Reduce(
union,
list(
rhyme,
non_matches
)
)
test_that("two phone rhyme third onset is correct", {
expect_setequal(lexicon[get_rhymes(target, lexicon, mismatch = 2)], rhyme)
})
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