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#' Length of longest continuous period above/below threshold
#'
#' This function finds the length of the longest continous period above/below
#' a specified threshold light level or within a specified range of light levels.
#'
#' @param Light.vector Numeric vector containing the light data.
#' @param Time.vector Vector containing the time data. Can be \link[base]{POSIXct},
#' \link[hms]{hms}, \link[lubridate]{duration}, or \link[base]{difftime}.
#' @param comparison String specifying whether the period of light levels above or
#' below threshold should be calculated. Can be either `"above"` (the default)
#' or `"below"`. If two values are provided for `threshold`, this argument will be ignored.
#' @param threshold Single numeric value or two numeric values specifying the
#' threshold light level(s) to compare with. If a vector with two values is provided,
#' the period of light levels within the two thresholds will be calculated.
#' @param epoch The epoch at which the data was sampled. Can be either a
#' \link[lubridate]{duration} or a string. If it is a string, it needs to be
#' either `"dominant.epoch"` (the default) for a guess based on the data, or a valid
#' \link[lubridate]{duration} string, e.g., `"1 day"` or `"10 sec"`.
#' @param loop Logical. Should the data be looped? Defaults to `FALSE`.
#' @param na.replace Logical. Should missing values (NA) be replaced
#' for the calculation? If `TRUE` missing values will not be removed but will
#' result in `FALSE` when comparing `Light.vector` with `threshold`.
#' Defaults to `FALSE`.
#' @param na.rm Logical. Should missing values (NA) be removed for the calculation?
#' If `TRUE`, this argument will override `na.replace`. Defaults to `FALSE`.
#' @param as.df Logical. Should a data frame be returned? If `TRUE`, a data
#' frame with a single column named `period_{comparison}_{threshold}` will be returned.
#' Defaults to `FALSE`.
#'
#' @return A duration object (see \code{\link[lubridate]{duration}}) as single value,
#' or single column data frame.
#'
#' @export
#'
#' @family metrics
#'
#' @examples
#'
#' N <- 60
#' # Dataset with continous period of >250lx for 35min
#' dataset1 <-
#' tibble::tibble(
#' Id = rep("A", N),
#' Datetime = lubridate::as_datetime(0) + lubridate::minutes(1:N),
#' MEDI = c(sample(1:249, N-35, replace = TRUE),
#' sample(250:1000, 35, replace = TRUE))
#' )
#'
#' dataset1 %>%
#' dplyr::reframe("Period >250lx" = period_above_threshold(MEDI, Datetime, threshold = 250))
#'
#' dataset1 %>%
#' dplyr::reframe("Period <250lx" = period_above_threshold(MEDI, Datetime, "below", threshold = 250))
#'
#' # Dataset with continous period of 100-250lx for 20min
#' dataset2 <-
#' tibble::tibble(
#' Id = rep("B", N),
#' Datetime = lubridate::as_datetime(0) + lubridate::minutes(1:N),
#' MEDI = c(sample(c(1:99, 251-1000), N-20, replace = TRUE),
#' sample(100:250, 20, replace = TRUE)),
#' )
#' dataset2 %>%
#' dplyr::reframe("Period 250lx" = period_above_threshold(MEDI, Datetime, threshold = c(100,250)))
#'
#' # Return data frame
#' dataset1 %>%
#' dplyr::reframe(period_above_threshold(MEDI, Datetime, threshold = 250, as.df = TRUE))
#'
period_above_threshold <- function(Light.vector,
Time.vector,
comparison = c("above", "below"),
threshold,
epoch = "dominant.epoch",
loop = FALSE,
na.replace = FALSE,
na.rm = FALSE,
as.df = FALSE) {
# Match input arguments
comparison <- match.arg(comparison)
# Perform argument checks
stopifnot(
"`Light.vector` must be numeric!" = is.numeric(Light.vector),
"`Time.vector` must be POSIXct, hms, duration, or difftime!" =
lubridate::is.POSIXct(Time.vector) | hms::is_hms(Time.vector) |
lubridate::is.duration(Time.vector) | lubridate::is.difftime(Time.vector),
"`Light.vector` and `Time.vector` must be same length!" =
length(Light.vector) == length(Time.vector),
"`threshold` must be numeric!" = is.numeric(threshold),
"`threshold` must be either one or two values!" = length(threshold) %in% c(1, 2),
"`epoch` must either be a duration or a string" =
lubridate::is.duration(epoch) | is.character(epoch),
"`loop` must be logical!" = is.logical(loop),
"`na.rm` must be logical!" = is.logical(na.rm),
"`as.df` must be logical!" = is.logical(as.df)
)
# Get the epochs based on the data
if (is.character(epoch) && epoch == "dominant.epoch") {
epoch <- count_difftime(tibble::tibble(Datetime = Time.vector))$difftime[1]
}
# If the user specified an epoch, use that instead
else {
epoch <- lubridate::as.duration(epoch)
}
# Loop data
if (loop) {
Light.vector <- c(Light.vector, Light.vector)
}
# Remove NAs
if(na.rm){
Light.vector <- Light.vector[!is.na(Light.vector)]
}
# Find longest period
longest_period <- function(x){
z <- c(x, 0)
z <- (cumsum(z) * c(diff(z) < 0, 0))
max(diff(c(0, 0, z[z != 0])))
}
out <- compare_threshold(Light.vector, threshold, comparison, na.replace) %>%
longest_period()
# As duration object
out <- lubridate::as.duration(out * epoch)
# Return data frame or numeric value
if (as.df) {
if(length(threshold) == 2){
comparison <- "within"
}
threshold <- stringr::str_flatten(sort(threshold), collapse = "-")
return(tibble::tibble("period_{comparison}_{threshold}" := out))
} else {
return(out)
}
}
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