Nothing
divide_list <- function(x, number) {
if (length(x) > number) {
rest <- length(x)%%number
if (rest == 0) {
result <- matrix(x, ncol = number, byrow = TRUE)
result <- split(result, row(result))
} else {
index <- length(x) - rest
result <- matrix(x[1:index], ncol = number, byrow = TRUE)
result <- split(result, row(result))
result[[length(result) + 1]] <- x[index + 1:length(x)]
length(result[[length(result)]]) <- length(x) - index
}
return(result)
} else {
return(as.vector(x))
}
}
#' Query a page by xpath means
#'
#' @param url URL of the page. Please note that this is different of the title of the wiki page.
#' @param xpath XPATH query to execute
#'
#' @import XML
#' @import RCurl
#'
#' @return A character vector
#' @export
xpath <- function(url, xpath) {
dom <- htmlParse(getURL(url, followlocation = TRUE, httpheader = c(`User-Agent` = "WikiSocio"), encoding = "UTF-8"))
return(xpathSApply(dom, xpath, xmlValue))
}
#' Recode a date vector into periods
#'
#' @param date A timestamp vector
#' @param period The breaks witch \code{date} sould be cut with
#'
#' @return a numeric vector with the periods replacing the date
#' @export
#'
period <- function(date, period = c("2005-05-01", "2009-12-01")) {
if (period == "year") {
period <- c("2001-01-01", "2002-01-01", "2003-01-01", "2004-01-01", "2005-01-01", "2006-01-01", "2007-01-01", "2008-01-01", "2009-01-01",
"2010-01-01", "2011-01-01", "2012-01-01", "2013-01-01", "2014-01-01", "2015-01-01", "2016-01-01")
}
period <- tryCatch(as.Date(period), error = function(e) stop("period is not a time vector"))
date <- tryCatch(as.Date(date), error = function(e) NA)
return(tryCatch(cut(date, breaks = c(as.Date("1900-01-01"), period, as.Date("3000-01-01"))), error = function(e) NULL))
}
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