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#' 2AFC For Dichotomous Observations And Ordinal Polychotomous Forecasts
#'
#' Routine to calculate the Generalized Discrimination Score (aka
#' Two-Alternatives Forced Choice Score 2AFC) for the situation of dichotomous
#' observations and (ordinal) polychotomous forecasts
#'
#' This routine applies Eq.5 of in Mason and Weigel (2009) to calculate the
#' 2AFC.
#'
#' @param obsv vector with dichotomous observations (values in {0,1})
#' @param fcst vector of same length as \emph{obsv} with polychotomous
#' forecasts (values in {1,..,m})
#' @param mf number of forecast categories (default = 3)
#' @return \item{ p.afc }{ Value of Generalized Discrimination (2AFC) Score }
#' @author Andreas Weigel, Federal Office of Meteorology and Climatology,
#' MeteoSwiss, Zurich, Switzerland
#' @seealso \code{\link{afc}}
#' @references S.J. Mason and A.P. Weigel, 2009. A generic verification
#' framework for administrative purposes. Mon. Wea. Rev., 137, 331-349
#' @keywords file
#' @examples
#'
#' #Forecasts and observations of Nino-3.4 index
#' #Load set of dichotomous observations and polychotomous forecasts (4 categories)
#' data(cnrm.nino34.dm)
#' obsv = cnrm.nino34.dm$obsv
#' fcst = cnrm.nino34.dm$fcst
#'
#' #Calculate skill score
#' afc.dm(obsv,fcst,4)
#'
#' @export afc.dm
afc.dm = function(obsv,fcst,mf=3){
#######################
# OBSV: DICHOTOMOUS #
# FCST: POLYCHOTOMOUS #
#######################
# input variables:
# ----------------
# mf - Number of categories (e.g. warning levels). Default = 3
# fcst - vector with warning level forecasts (values 1,2,...,ncat)
# obsv - vector with corresponding observations (values 0 and 1)
# output variable:
# ----------------
# p.afc - 2AFC skill score as obtained from MW09 Eq. (5)
n1 = sum(obsv)
n0 = length(obsv)-sum(obsv)
# Condition forecasts on whether or not an event has occurred
fcst.1 = fcst[which(obsv == 1)]
fcst.0 = fcst[which(obsv == 0)]
if (mf == 1) stop("Please enter n/o categories")
# Condition forecast categories on whether or not an event has occurred
n0.mf = array(NA,mf)
n1.mf = array(NA,mf)
for (i in 1:mf){
n0.mf[i] = length(which(fcst.0 == i))
n1.mf[i] = length(which(fcst.1 == i))
}
# Calculate Eq. 5 of MW09
summand1 = 0
summand2 = 0
for (i in 1:(mf-1)) for (j in (i+1):mf)
summand1 = summand1 + n0.mf[i]*n1.mf[j]
for (k in 1:mf)
summand2 = summand2 + n0.mf[k]*n1.mf[k]
p.afc = (summand1 + 0.5*summand2)/(n0*n1)
type.flag = 1
return(p.afc)
}
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