kendall.u: Kendall's Coefficient of Agreement

Description Usage Arguments Details Value References See Also Examples

View source: R/kendall.u.R

Description

Kendall's u coefficient of agreement between judges.

Usage

1
kendall.u(M, cont.correct = FALSE)

Arguments

M

a square matrix or a data frame consisting of absolute choice frequencies; row stimuli are chosen over column stimuli

cont.correct

logical, if TRUE a correction for continuity is applied (by deducting 1 from chi2), default is FALSE

Details

Kendall's u takes values between min.u (when agreement is minimum) and 1 (when agreement is maximum). The minimum min.u equals -1/(m - 1), if m is even, and -1/m, if m is odd, where m is the number of subjects (judges).

The null hypothesis in the chi-square test is that the agreement between judges is by chance.

It is assumed that there is an equal number of observations per pair and that each subject judges each pair only once.

Value

u

Kendall's u coefficient of agreement

min.u

the minimum value for u

chi2

the chi-square statistic for a test that the agreement is by chance

df

the degrees of freedom

pval

the p-value of the test

References

Kendall, M.G., & Smith, B.B. (1940). On the method of paired comparisons. Biometrika, 31, 324–345.

See Also

eba, strans, circular.

Examples

1
2
data(celebrities)
kendall.u(celebrities)  # moderate agreement

Example output

Kendall's u coefficient of agreement

u = 0.1171759, minimum u = -0.004291845
chi2 = 1027.812, df = 36, p-value = 0
alternative hypothesis: between-judges agreement is not by chance
correction for continuity has not been applied

eba documentation built on May 29, 2017, 4:26 p.m.

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