list_str: Summarise the structure of a list

In listless: Convert Lists to Tidy Data Frames

Description

Summarise the structure of a list, in a tidy data frame.

Usage

list_str(l, name_variables = "names",
  stringsAsFactors = getOption("stringsAsFactors"))

Arguments

l	A variable, probably a list.
name_variables	A string. What should the columns formed from the names of l be called?
stringsAsFactors	Should character columns be converted to factors?

Value

data.frame.

See Also

str, list_to_data.frame

Examples

l <- list(
  a = 1,
  b = matrix(1:6, 2),
  c = list(
    ca = y ~ x,
    list(cba = median, cbb = quote(1 + 1), cbc = expression(1 + 1)),
    cc = list(cca = as.name("xyz"))
  ),
  d = array(1:24, 2:4)
)
list_str(l)

listless documentation built on May 2, 2019, 1:08 p.m.