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bonode<-function(Gmat,y,Xmat,tr,dmatrow,dmatsg,parent,parvec,w,nsplit,crit=crit) {
#selects best observed parent node
#create matrix to keep the highest value of the criterion
nleaf <- ncol(Gmat)
critmax <- matrix(0,nrow=nleaf,ncol=7)
critmax[,1] <- 1:nleaf
dmatsel <- matrix(0,nrow=dim(dmatsg)[1],ncol=nleaf)
dmatsel <- sapply(1:nleaf,function(kk,dmatrow,dmatsg,nleaf){ ifelse(apply(dmatsg[,c(nleaf,nleaf+1)]==dmatrow[kk],1,sum)!=2,1,0)},nleaf=nleaf,dmatrow=dmatrow,dmatsg=dmatsg)
critmax[,c(2:7)] <- t(sapply(1:nleaf,function(kk,y,Xmat,tr,Gmat,dmatsg,dmatsel,parent,parvec,w,nsplit,crit){
bovar(y,Xmat,tr,gm=Gmat[,kk],dmatsg,dmatsel=dmatsel[,kk],parents=parent[-kk,],parvec,w,nsplit,crit=crit) },
Xmat=Xmat,Gmat=Gmat,y=y,tr=tr,parent=parent,nsplit=nsplit,w=w,parvec=parvec,dmatsg=dmatsg,dmatsel=dmatsel,crit=crit) )
#which predictor is the best splitting candidate for this split?
bestrow <- which(critmax[,5]==max(critmax[,5])) [1]
return(critmax[bestrow,])
}
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