list2df: Convert a list to a data frame
In PNNL-Comp-Mass-Spec/glmnetGLR: glmnetGLR

Description Usage Arguments Details Value Author(s) Examples

Convert a list of vectors (or data frames) with same numbered lengths (or number of columns) into a data frame.

1 2	list2df(vList, col.names = NULL, row.names = NULL, convert.numeric = TRUE, strings.as.factors = FALSE)

`vList`	List of vectors or data frames, each vector having the same length, `n`, or each data frame having the same number of columns, `n`.
`col.names`	Optional character vector of length `n` with column names that will be given to the output data frame. If `col.names = NULL`, column names are extracted if possible from the column names (or names) of the data frames (or vectors).
`row.names`	Optional character vector with length equivalent to the length of `vList` containing the row names of the output data frame. If `row.names = NULL`, row names from the data frames (or names of the `vList` elements) if possible.
`convert.numeric`	If `vList` is list of vectors, `= TRUE` attempts to convert each column to numeric if possible using `as.numeric.silent`
`strings.as.factors`	If `vList` is a list of vectors, `= TRUE` converts character variables into factors using `factor2character`.

It is permissible for vList to contain NULL elements. list2df performs numerous consistency checks to ensure that contents of vList which are combined into the resulting data frame are conformable, labeled consistently, of the equivalent class when necessary, etc.

If vList is list of data frames, a data frame resulting from efficiently row binding the data frames in vList is returned. If vList is a list of vectors, a data frame is returned where the first column contains the first elements of the list vectors, the second column contains the second elements of the list vectors, etc.

Landon Sego

# For a list of data frames
z <- list(d1 = data.frame(a = 1:10, b = letters[1:10]),
          d2 = data.frame(a = 11:15, b = letters[11:15]))
list2df(z)

# For a list of vectors
x <- c("r1c1 1", "r2c1 2", "r3c1 3", "r4c4 4")
y <- strsplit(x, "\ ")
list2df(y)
list2df(y, col.names=LETTERS[1:2])

z <- list(NULL, a = c(top = 10, bottom = 12), NULL, b = c(top = 15, bottom = 17))
list2df(z)