convertUnicode <- function(char.vec) {
# might need to convert to char in case we get handing a
# numeric vector in a column...
char.vec <- as.character(char.vec)
# look for the "\\u" string
has_u <- grepl("\\u", char.vec, fixed=TRUE)
# if there is nothing to do then return the strings unharmed
if (!any(has_u)) return(char.vec)
# else we need to find the code attached to the strings
# and convert it
has_u_index <- which(has_u)
for (j in has_u_index) {
string_split <- strsplit(char.vec[j], "\\u", fixed=TRUE)[[1]]
# so... we might have multiple parts
for (k in 2:(length(string_split))) {
string_part <- string_split[k]
# the first four are the hex representation of the unicode string
hex_part <- substr(string_part, 1, 4)
# interpret as hex and convert to integer
int_part <- strtoi(hex_part, base=16L)
# convert to Unicode
unicode_part <- intToUtf8(int_part)
# re-paste together the string
new_string <- paste0(unicode_part, substr(string_part, 5, nchar(string_part)))
# replace the entry in string_split
string_split[k] <- new_string
}
# replace the char.vec entry
char.vec[j] <- paste(string_split, collapse="")
}
return(char.vec)
}
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