SpatialPixelsDataFrame-class: Class "SpatialPixelsDataFrame"

Description Objects from the Class Slots Extends Methods Author(s) See Also Examples

Description

Class for spatial attributes that have spatial locations on a regular grid.

Objects from the Class

Objects can be created by calls of the form as(x, "SpatialPixelsDataFrame"), where x is of class SpatialPointsDataFrame-class, or by importing through rgdal. Ordered full grids are stored instead or unordered non-NA cells;

Slots

bbox:

Object of class "matrix"; bounding box

proj4string:

Object of class "CRS"; projection

coords:

see SpatialPoints; points slot

coords.nrs

see SpatialPointsDataFrame

grid:

see GridTopology-class; grid parameters

grid.index:

integer; index of points in the list to points in the full (ordered) grid. x cycles fastest; all coordinates increase from low to hight except y, which decreases from high to low

data:

Object of class data.frame, containing the attribute data

Extends

Class "SpatialPixels", directly. Class "Spatial", by class "SpatialPixels".

Methods

coordinates

signature(x = "SpatialPixelsDataFrame"): retrieves coordinates

[

signature(x = "SpatialPixelsDataFrame"): selects row(s) and/or attribute(s), and returns an object of class SpatialPixelsDataFrame; rows refer here to the pixel numbers, not grid lines. For selecting a square block in a grid, coerce to a SpatialGridDataFrame-class first, and use [ on that object

as.matrix

signature(x = "SpatialPixelsDataFrame"): coerce to matrix

rbind

signature(x = "SpatialPixelsDataFrame"): rbind-like method

Author(s)

Edzer Pebesma, [email protected]

See Also

SpatialPixels-class, which does not contain the attribute data

Examples

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data(meuse.grid) # only the non-missing valued cells
coordinates(meuse.grid) = c("x", "y") # promote to SpatialPointsDataFrame
gridded(meuse.grid) <- TRUE # promote to SpatialPixelsDataFrame
meuse.grid[["idist"]] = 1 - meuse.grid[["dist"]] # assigns new attribute
image(meuse.grid["idist"]) # note the single [

# toy example:
df = data.frame(z = c(1:6,NA,8,9),
    xc = c(1,1,1,2,2,2,3,3,3),
    yc = c(rep(c(0, 1.5, 3),3)))
coordinates(df) = ~xc+yc
gridded(df) = TRUE
image(df["z"])
# draw labels to verify:
cc = coordinates(df)
z=df[["z"]]
zc=as.character(z)
zc[is.na(zc)]="NA"
text(cc[,1],cc[,2],zc)

dis-organization/sp_dplyrexpt documentation built on May 15, 2019, 8:52 a.m.